Answer:
See all the answers below.
Step-by-step explanation:
by² = d
Jay = 6
ay - cy = d.
cy - b) = y
Option A
by² = d
divide both side by b
y² = d/b
square both sides
y=√d/b
Option B
Jay = 6
Divide both sides by Ja
y= 6/Ja
Option C
ay - cy = d
y(a-c)=d
divide both sides by (a-c)
y= d/(a-c)
Option D
(cy - b) = y
y-cy=-b
y(1-c)=-b
y= -b/(1-c)
Steps:
1) determine the domain
2) determine the extreme limits of the function
3) determine critical points (where the derivative is zero)
4) determine the intercepts with the axis
5) do a table
6) put the data on a system of coordinates
7) graph: join the points with the best smooth curve
Solution:
1) domain
The logarithmic function is defined for positive real numbers, then you need to state x - 3 > 0
=> x > 3 <-------- domain
2) extreme limits of the function
Limit log (x - 3) when x → ∞ = ∞
Limit log (x - 3) when x → 3+ = - ∞ => the line x = 3 is a vertical asymptote
3) critical points
dy / dx = 0 => 1 / x - 3 which is never true, so there are not critical points (not relative maxima or minima)
4) determine the intercepts with the axis
x-intercept: y = 0 => log (x - 3) = 0 => x - 3 = 1 => x = 4
y-intercept: The function never intercepts the y-axis because x cannot not be 0.
5) do a table
x y = log (x - 3)
limit x → 3+ - ∞
3.000000001 log (3.000000001 -3) = -9
3.0001 log (3.0001 - 3) = - 4
3.1 log (3.1 - 3) = - 1
4 log (4 - 3) = 0
13 log (13 - 3) = 1
103 log (103 - 3) = 10
lim x → ∞ ∞
Now, with all that information you can graph the function: put the data on the coordinate system and join the points with a smooth curve.
Answer:
(-3)^2
Step-by-step explanation:
You add 7 on both sides, giving you x^2 - 6x = 7
Then, take half of b, and square it. Giving you x^2 - 6x +(-3)^2 = 7
The answer will be (-3)^2 for this question, but this is not the full solution.
Hope this helped. Good luck on the rest!
Answer:
Region D.
Step-by-step explanation:
Here we have two inequalities:
y ≤ 1/2x − 3
y < −2/3x + 1
First, we can see that the first inequality has a positive slope and the symbol (≤) so the values of the line itself are solutions, this line is the solid line in the graph.
And we have that:
y ≤ 1/2x − 3
y must be smaller or equal than the solid line, so here we look at the regions below the solid line, which are region D and region C.
Now let's look at the other one:
y < −2/3x + 1
y = (-2/3)*x + 1
is the dashed line in the graph.
And we have:
y < −2/3x + 1
So y is smaller than the values of the line, so we need to look at the region that is below de dashed line.
The regions below the dashed line are region A and region D.
The solution for the system:
y ≤ 1/2x − 3
y < −2/3x + 1
Is the region that is a solution for both inequalities, we can see that the only region that is a solution for both of them is region D.
Then the correct option is region D.
