Answer:
Hey there!
5. f(4) is 3. f(3) is 2. Thus, f[f(4)]=2
6. g(2) is 3. g(3) is 1. g[g(2)]=1
Hope this helps :)
Answer:
the given expression is equivalent to
Step-by-step explanation:
![2(x - 3) {}^{2} \\ 2( {x}^{2} - 2.x.3 + {3}^{2} ) \\ using \: formula \: (x - y) {}^{2} = x {}^{2} - 2.x.y + y {}^{2} \\ 2(x {}^{2} - 6x + 3) \\ 2 {x}^{2} - 12x + 6](https://tex.z-dn.net/?f=2%28x%20-%203%29%20%7B%7D%5E%7B2%7D%20%20%5C%5C%202%28%20%7Bx%7D%5E%7B2%7D%20%20-%202.x.3%20%2B%20%20%7B3%7D%5E%7B2%7D%20%29%20%5C%5C%20using%20%5C%3A%20formula%20%5C%3A%20%28x%20-%20y%29%20%7B%7D%5E%7B2%7D%20%20%3D%20x%20%7B%7D%5E%7B2%7D%20%20-%202.x.y%20%2B%20y%20%7B%7D%5E%7B2%7D%20%20%5C%5C%202%28x%20%7B%7D%5E%7B2%7D%20%20-%206x%20%2B%203%29%20%5C%5C%202%20%7Bx%7D%5E%7B2%7D%20%20-%2012x%20%2B%206)
Answer:
(The common base is 2).
Step-by-step explanation:
You have the equation given in the problem:
![2^{(x+3)}-3=5](https://tex.z-dn.net/?f=2%5E%7B%28x%2B3%29%7D-3%3D5)
Then base of
is 2. Therefore, the common base must be 2.
If you add 3 to both sides of the equation, you obtain:
![2^{(x+3)}-3+3=5+3](https://tex.z-dn.net/?f=2%5E%7B%28x%2B3%29%7D-3%2B3%3D5%2B3)
![2^{(x+3)}=8](https://tex.z-dn.net/?f=2%5E%7B%28x%2B3%29%7D%3D8)
If you descompose 8 into its prime factors, you obtain that it can be written as:
8=2*2*2=2³
Therefore, you can you rewrite each side of the equation as following:
![2^{(x+3)}=2^{3}](https://tex.z-dn.net/?f=2%5E%7B%28x%2B3%29%7D%3D2%5E%7B3%7D)
Where the common base is 2.
f(x) = -3x + 6
y = -3x + 6
x = -3y + 6
x - 6 = -3y
-3 -3
⁻¹/₃x + 2 = y
⁻¹/₃x + 2 = f⁻¹(x)
g(x) = x + 2
y = x + 2
x = y + 2
x - 2 = y
x - 2 = g⁻¹(x)
W = 84
L = w - 14
L = 84 - 14 = 70
so the team lost 70 games
and they played 70 + 84 = 154 games