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3 years ago

What is the total surface area?

Mathematics

1 answer:

Elanso [62]3 years ago

3 0

Answer:

231.5in squared

Step-by-step explanation:

Both faces area formula

Rectangle: l x w

triangle: b x h / 2

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Grant is trying to make money to help pay for college by taking a job with Brian’s bike taxis if Baltimore. He has an agreement

alexandr402 [8]

Grant needs to ride at least 13.33 miles to male at least $ 15.00 a day

<em><u>Solution:</u></em>

Given that Grant has an agreement with Brian to rent the bike for $35.00 a night

He charges customers $3.75 for every mile he transports them

Grant needs to make at least $15.00 a day

To find: miles needed to ride

From given question, He charges customers $3.75 for every mile he transports them

So if he transports for "x" miles he would get,

$\$ 3.75 \times x = \$ 3.75x$

So the profit he gets is $ 3.75 and initial cost invested to rent bike is $ 35. Also, Grant needs to make at least $15.00 a day

So we can frame a inequality as:

$3.75x - 35 \geq 15\\\\3.75x\geq 35 + 15\\\\3.75x\geq 50\\\\x \geq 13.33$

So he needs to ride atleast 13.33 miles to male atleast $ 15.00 a day

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3 years ago

Omg!! Please help!! Thank you

nordsb [41]

Answer:

the first one since it shows all the lines being equal and therefore making the angles equal

8 0

3 years ago

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Conduction can occur within a single substance, but parts of the substance must have which property? different temperatures diff

Julli [10]

Answer:

Step-by-step explanation:

answer is A

6 0

3 years ago

Read 2 more answers

Show two different ways to factor -4x - 28

horsena [70]

Step-by-step explanation:

-4x - 28

x = -28 + 4

x = -24

I HOPE THIS IS CORRECT IN ONLY THIS WAY SORRY IF IT IS WRONG

CAN YPU MARK ME AS BRAINLIEST

5 0

3 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is:

$(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})$

$(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]$

$(x,y) = (10.452, 34.531)\,[km]$

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

$\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}$

$\theta \approx 16.840^{\circ}$

And the distance from the camp is calculated by the Pythagorean Theorem:

$r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}$

$r = 36.078\,km$

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0

3 years ago