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2 years ago

PLEASE HELP I WILL MARK YOU BRAINLIEST determine the exact and approximat solutions for 4(x + 5)^2 = 21 show your steps

Mathematics

1 answer:

BabaBlast [244]2 years ago

4 0

Answer:

x = − 5 + 1/2 √ 21 or x = − 5 + − 1/2 √ 21

Step-by-step explanation:

Let's solve your equation step-by-step.

4(x+5)^2=21

Step 1: Simplify both sides of the equation.

4x^2+40x+100=21

Step 2: Subtract 21 from both sides.

4x^2+40x+100−21 =21−21 4x^2+40x+79=0

For this equation: a=4, b=40, c=79

4x^2+40x+79=0

Step 3: Use quadratic formula with a=4, b=40, c=79.

x= −b±√ b^2−4ac/2ax

= −(40)+√ (40)^2−4(4)(79)/2(4)

x = 40^2±√ 336/8

x= −5+1/2 √ 21 or x = −5+ − 1/2√ 21

Answer: x = − 5 + 1/2 √ 21 or x = − 5 + − 1/2 √ 21

( I hope this was helpful) >;D

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