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Tanzania [10]
2 years ago
8

Marcela finished the race in 75.8 minutes. Rebecca finished the race in 8.1/2 minutes faster then Marcela. How many minutes did

it take Rebecca to finish the race?
Mathematics
1 answer:
Bond [772]2 years ago
5 0

Answer: 67.3

Step-by-step explanation:

turn the "\frac{1}{2}" into .5 and substract

75.8

-  8.5

----------

67.3

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Casandra is training for a 10 mile race.On the first day of training she runs 4 miles, each day after that sge adds on 0.5 mile.
AnnyKZ [126]

Answer:

8 days

Step-by-step explanation:

3 0
3 years ago
There are 99 males and 121 females participating in a marathon. What percent of the participants are female?​
ioda

To do this, we first want to see how many participants there are in total by adding both males and females.

99+121=220

Now we know that there were 220 total participants, but only 121 were females.

This allows us to set up the fraction 121/220= the percent female.

\frac{121}{220} =0.55

or 55%

8 0
3 years ago
1.3/4 - 5 3/7 <br> 2.-9 3/10 - 2/11
kodGreya [7K]
1)\\\\\frac{3}{4}-5\frac{3}{7}\\\\\frac{3}{4}-\frac{38}{7}\\\\\frac{3}{4}*\frac{7}{7}-\frac{38}{7}*\frac{4}{4}\\\\\frac{21}{28}-\frac{152}{28}\\\\\frac{-131}{28}\\\\-4\frac{19}{28}\\\\\\2)\\\\-9\frac{3}{10}-\frac{2}{11}\\\\\frac{-93}{10}-\frac{2}{11}\\\\\frac{-93}{10}*\frac{11}{11}-\frac{2}{11}*\frac{10}{10}\\\\\frac{-1023}{110}-\frac{20}{110}\\\\\frac{-1043}{110}\\\\-9\frac{53}{110}
3 0
3 years ago
The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the
ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/\sqrt{n})

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/\sqrt{n}

The upper limit => C.I_u = μ + Z*σ/\sqrt{n}

The lower limit => C.I_l = μ - Z*σ/\sqrt{n}

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/\sqrt{n})

                                    = 200 + (1.96*30)/\sqrt{n}

                                    = 200 + 58.8/\sqrt{n}

5 0
3 years ago
Hi can you please help I’ve been stuck on this question
sveta [45]

9514 1404 393

Answer:

  20 meters

Step-by-step explanation:

Using the formula for the area of a rectangle, fill in the given information and solve for the unknown.

  A = LW . . . . . . . . area is length × width

  80 m² = L·(4 m)

  (80 m²)/(4 m) = L = 20 m . . . . . . . divide by 4m (the coefficient of L)

The tarp is 20 meters long.

4 0
3 years ago
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