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2 years ago

8

Marcela finished the race in 75.8 minutes. Rebecca finished the race in 8.1/2 minutes faster then Marcela. How many minutes did

it take Rebecca to finish the race?

1 answer:

Bond [772]2 years ago

5 0

Answer: 67.3

Step-by-step explanation:

turn the " $\frac{1}{2}$ " into .5 and substract

75.8

- 8.5

----------

67.3

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The graph of f(x) = 2x + 1 is shown below. Explain how to find the average rate of change between x = 2 and x = 5. (10 points) G

levacccp [35]

First we need to find f(2) and f(5), which are 5 and 11 respectively; all you have to do is plug in 2 and 5.

Then, we use the following formula:

(f(b)-f(a))/(b-a),

where b and a are the largest and smallest x values respectively.

Finally, we plug our values in:

(11-5)/(5-2)=6/3=2

In fact, the average rate of change of any linear function is just the coefficient of the x term. Hope this helped!

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3 years ago

A school store ordered 12 boxes of notebooks. For each box they paid for, their bank account said -$16.50. What did their bank a

SashulF [63]

Answer:

-198 dollars

Step-by-step explanation:

6 0

3 years ago

Someone help!! thanks :)))

cupoosta [38]

Answer:

10

Step-by-step explanation:

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8 0

3 years ago

A) Let X be a random variable that can assume only positive integer values, and assume its probability function is P(X -n) A/3^n

kramer

Answer:

a) The value of A = 2

b) The value of $B = \dfrac{1}{12}$

Step-by-step explanation:

a)

Given that:

X should be the random variable that assumes only positive integer values.

The probability function; $P[X = n] = \dfrac{A}{3^n}$ for some constant A and n ≥ 1.

Then, let $\sum \limits ^{\infty}_{n =1} P[X =n] = 1$

This implies that:

$A \sum \limits ^{\infty}_{n =1} \dfrac{1}{3^n}= 1$

$A \times \dfrac{\dfrac{1}{3}}{1 - \dfrac{1}{3}} = 1$

$A \times \dfrac{\dfrac{1}{3}}{\dfrac{2}{3}} = 1$

$A \times \dfrac{1}{2}=1$

A = 2

Thus, the value of A = 2

b)

Suppose X represents a e constant A (n> 1). Find A.

b) Let X be a continuous random variable that can assume values between 0 and 3

Then, the density function of x is:

$f_x(x) = \left \{ {{B(x^2+1)} \ \ \ 0 \le x \le 3 \ \ \ \atop {0} \ \ \ otherwise} \right.$

where; B is constant.

Then, using the property of the probability density function:

$\int ^3_0 \ B (x^2+1 ) \ dx = 1\\$

Taking the integral, we have:

$B \Big [\dfrac{x^3}{3} +x \Big ]^3_0 = 1$

$B \Big [\dfrac{3^3}{3} +3 \Big ]= 1$

$B \Big [\dfrac{27}{3} +3 \Big ] = 1$

B [ 9 +3 ] = 1

B [ 12 ] = 1

Divide both sides by 12

$B = \dfrac{1}{12}$

5 0

3 years ago

(5x-8)+(4x+7) simplify

Elanso [62]

Heya!!!

Answer to your question:

(5x-8)+(4x+7)

=5x+4x -8+7

=9x-1

Hope it helps *_*

5 0

3 years ago

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