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Crazy boy [7]
3 years ago
6

Which of the following numbers are in the domain of the function? Select three that apply.

Mathematics
1 answer:
kipiarov [429]3 years ago
7 0

Answer:

-15.2, -8, and -2

Step-by-step explanation:

Hello There!

If you didn't know the domain is the set of x values of a function

in the given function the domain could represented like this

x ≤-2

so anything that is -2 or less than -2 is considered a domain of the function

( how we found the set of x values: it was found by looking at the function. The function starts at (-2,-1) and goes up to the right with a constant rate of change.) This meaning that the domain could be represented by x ≤-2

-8 is less than -2 therefore it is a domain of the function

- 15.2 is less than -2 therefore is is a domain of the function

-2 is equal to -2 therefore is is a domain of the function

-1 is not less than -2 therefore it is not a domain of the function  

2.5 and 10 are also not less than -2 therefore they are not domains to the function

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Lily's room is 30 sq. ft. Her bed takes up 2/4 of the room. How many sq. ft. is left?
natali 33 [55]
Okay, so her room is 30 sq ft right and her bed takes up 2/4. 2/4 is the same thing as 1/2 (half of her room.) Now, you need to find one half of 30 (30 / 2), that is 15. So if her bed takes up 15 sq ft, subtract that from the total area of the room. 30-15= 15 sq ft. This means that 15 sq ft of her room are left! :) 

Hope that makes sense!
3 0
3 years ago
Read 2 more answers
Mr. Neville Iceguy mixed up 12 3/5 gallons of chili for a party. If 7 3/4 gallons of chili was mild, and the rest was extra spic
mihalych1998 [28]

Answer:

4\frac{17}{20}

Step-by-step explanation:

We have been given that  Mr. Neville Iceguy mixed up 12 3/5 gallons of chili for a party. 7 3/4 gallons of chili was mild.

To find the amount of extra spicy chili, we will subtract amount of mild chili from total chili as:

12\frac{3}{5}-7\frac{3}{4}

Convert mixed fraction into improper fraction:

12\frac{3}{5}\Rightarrow \frac{12\times 5+3}{5}=\frac{60+3}{5}=\frac{63}{5}

7\frac{3}{4}\Rightarrow \frac{7\times 4+3}{4}=\frac{28+3}{4}=\frac{31}{4}

12\frac{3}{5}-7\frac{3}{4}\Rightarrow\frac{63}{5}-\frac{31}{4}

Make a common denominator:

\frac{63*4}{5*4}-\frac{31*5}{4*5}

\frac{252}{20}-\frac{155}{20}

Combine numerators:

\frac{252-155}{20}

\frac{97}{20}

4\frac{17}{20}

Therefore, Mr. Iceguy made 4\frac{17}{20} gallons of extra spicy chili.

3 0
3 years ago
Hurry i'll give brainiest if u help me
galben [10]
X^2 = b^2-c^2
x^2= sqrt117^2-6^2
x^2=sqrt117×sqrt117-36
x^2=117-36
x^2=81
x=sqrt81
x=9cm
6 0
3 years ago
Joe is making a recipe that calls for ¾ teaspoons of cinnamon. His only measuring spoon holds 1/8 teaspoon. How many times will
Fittoniya [83]
3/4 would be the same as 6/8 so he will need to fill his spoon 6 times.
Hope this helped :)
6 0
3 years ago
The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. The article "Testing P
zysi [14]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: breakdown voltage of an insulating liquid under certain conditions.

a)

Graphic in attachment.

Box: The median is closer to the third quartile than the first quartile showing skewness to the left.

The black dot in the middle of the box represents the sample mean (X[bar]) as you can see it is also moved to the right side of the distribution, affected by the presence of an outlier.

Whiskers:

The upper whisker is smaller than the lower one and there is a value that can be considered an outlier.

Altogether you can say that the distribution of the data set is skewed to the left.

b)

To estimate the population mean you need the population to be at least normal. The box plot shows that the distribution is not symmetrical but, considering that the sample size is n= 48 you can apply the Central Limit Theorem and approximate the sampling distribution to normal.

X[bar]≈N(μ;σ²)

As the distribution is approximate, using the sample standard deviation (since we don't know the population value) for the distribution standard deviation is also valid ⇒ Z= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

∑X= 2626 ∑X²= 144950 n= 48

X[bar]= ∑X/n= 2626/48= 54.71

S²= 1/n[∑X²- (∑X)²/n]= 1/47[144950-(2626)²/48]= 27.36

S= 5.23

Z_{1-\alpha /2}= Z_{0.975}= 1.96

54.71 ± 1.96 * \frac{5.23}{\sqrt{48} }

[53.22; 56.18]kV

c)

95% CI

amplitude a=2 kV  i.e. semi amplitude d= 1 kV

The semi amplitude or margin of error for the CI can be calculated as:

d= Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

From this formula you can clear the sample size

\frac{d}{Z_{1-\alpha /2}} = \frac{S}{\sqrt{n} }

(\frac{d}{Z_{1-\alpha /2}} )*\sqrt{n} = S

\sqrt{n} = S* (\frac{Z_{1-\alpha /2}}{d} )

n = (S* (\frac{Z_{1-\alpha /2}}{d} ))^2

n= (5.23*(\frac{1.96}{1} ))^2= 105.08= 106

3 0
3 years ago
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