Answer:
E
Explanation
The structure of saturated fats are not flexible unlike unsaturated fats. ALso in the diagram, there are no double bonds which are present in unsaturated lipids, eliminating A and B. Triglycerides have 3 fatty acids shown with 3 carbons that are connected with long bonds unlike phospholipids that has 2 fatty acids. Therefore the answer is E.
Usually the lava flows come towards the end of the eruption, once the magma has lost enough of its volatiles to flow more quietly. Cinder cone eruptions are comparatively short lived, and thus cinder cones are much smaller features than stratovolcanoes and shield volcanoes (usually no more than a mile at the base).
Answer: The given statement is true.
Explanation: Ionization energy is defined as the amount of energy required to remove an electron from the outermost shell of an isolated gaseous atom.
General equation of ionization energy is given by:

- If the outermost electron is loosely bound to the nucleus which means that the electron can be easily removed form an atom, it will require less amount of ionization energy.
- And if the outermost electron is tightly bound to the nucleus which means that the electron cannot be removed easily from an atom. And hence, it will require more ionization energy.
Hence, the given statement is true.
Plotting a graph of the mass or volume of the product created against time allows you to determine the reaction's pace. This is depicted for two reactions on the graph. The rate of reaction is inversely proportional to the gradient of the line; that is, the steeper the line, the higher the rate of reaction
<h3>What is Rate of reaction ?</h3>
The result is a straight line with a positive gradient on a graph of reaction rate against concentration (a graph showing proportionality).
- The half-life is constant in a concentration-time graph of first order. As a result, the period of time it takes for the concentration to decrease to 50% of its initial value is constant.
- It would be considered first order if you obtained a straight line with a negative slope. If you graph the inverse of the concentration for second order
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