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3 years ago

90 POINTS IT YOU ANSWER THIS QUESTION CORRECTLY PLEASE HELP

1 answer:

6 0

Just take the area of the whole backyard(look up the formula for area of a trapezoid) then if I’m right just subtract the area of the flower gardens

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Courtney walks 4 laps around 1/4 mile back. 1 mile is 5280 feet, how far did she walk

Alika [10]

Answer:

5280 feet

Step-by-step explanation:

one loop is 1 fourth of a mile

she walked 4 times, making it a full mile.

So, she walked 5,280 feet in total

8 0

3 years ago

There are three circular tabletops with diameters of 5 ft, 7 ft, and 9 ft. Identify the area of each table top rounded to the ne

ella [17]

It is almost about 19.6; 38.5; 63.6

6 0

3 years ago

Harrison can purchase 4 dvds for $19.99 or 6 dvds for $22.50 which is the better deal?

adelina 88 [10]

$19.99 x 4 = $79.96

$22.50 x 6 = $135

$19.99 x 6 = $119.94

$22.50 x 4 = $90

The best answer to this choice is 4 dvds for $19.99. why?, because if it was 6 or 4 dvds for $19.99 the price would be more inexpensive then the price for $22.50, because if it was 22.50 x 4 or 6 dvds the price would be more expensive.

8 0

3 years ago

Write a x (-a)x 13 x a x (-a) x 13 in power notation

miss Akunina [59]

Answer:

$a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Step-by-step explanation:

The given expression

$a\times (-a)\times 13\times a\times (-a)\times 13$

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

$a\times (-a)\times 13\times a\times (-a)\times 13$

= $[13\times13][(a\times (-a)\times a\times (-a)]$

$13\times13 = 13^{2}$ , $a\times a = a^{2}$ , $(-a)\times (-a) = (-a)^{2}$

So,

$=[13^{2}][a^2\times (-a)^2]$

$(-a)^2 = a^{2}$

So,

$=[13^{2}][a^2\times a^2]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=[13^{2}][a^{2+2}]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=13^{2}\times a^{4}$

$=a^{4}\times 13^{2}$

Therefore, $a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Keywords: power notation

Learn more about power notation from brainly.com/question/2147364

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5 0

2 years ago

Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th

VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

$f(x)=16-\frac{x^2}{3}$

To find $f(-64)$ , we substitute $x=-64$ into the function.

$f(-64)=16-\frac{(-64)^2}{3}$

$f(-64)=16-\frac{4096}{3}$

$f(-64)=-\frac{4048}{3}$

To find $f(64)$ , we substitute $x=64$ into the function.

$f(64)=16-\frac{(64)^2}{3}$

$f(64)=16-\frac{4096}{3}$

$f(64)=-\frac{4048}{3}$

To find $f'(c)$ , we must first find $f'(x)$ .

$f'(x)=-\frac{2x}{3}$

This implies that;

$f'(c)=-\frac{2c}{3}$

$f'(c)=0$

$\Rightarrow -\frac{2c}{3}=0$

$\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}$

$c=0$

For this function to satisfy the Rolle's Theorem;

It must be continuous on $[-64,64]$ .

It must be differentiable on $(-64,64)$ .

and

$f(-64)=f(64)$ .

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0

2 years ago

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