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konstantin123 [22]
2 years ago
13

Im lazy dont ask please-

Mathematics
1 answer:
Helen [10]2 years ago
5 0

Answer:

0.75

or 3/4ths

Step-by-step explanation:

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PLEASE HELPPPP ! 16^x=64^x+4
Vladimir [108]

Answer:

x = -12

Step-by-step explanation:

Set logs up on both sides-

log 16^x = log 64^x+4

The variable goes behind because of the exponent log <em>property</em> (exponents are permitted to go behind the log to multiply)-

x * log 16 = x + 4 * log 64

Divide both logs out-

log 64/log 16 = 1.5

Simplify-

x = x+4(1.5)

1.5x + 6 = x

Remove 1.5-

1 - 1.5 = -.5x

Simplify-

-.5x = 6

Divide both sides-

6/-.5x = -12

Hence, the answer would be -12

4 0
3 years ago
Enter 52.16 in expanded form.
ivolga24 [154]

Answer:

50 + 2 + 0.1 + 0.06

5 0
3 years ago
Read 2 more answers
ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?
MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = \sqrt{(x_2-x_1)^2 +( y_2-y_1)^2

Step 1: Finding the length of  EF

By using distance formula,

EF = \sqrt{(-7 - 0)^2 + (4-0)^2}

EF = \sqrt{(49) + (16)}

EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\

Step 2: Finding the length of  FG

By using distance formula,

FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}

Step 2: Finding the length of  GE

GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8

Thus we could see that the sides EF = FG

So it is  a isosceles triangle.

6 0
3 years ago
What do you think the answer is
amid [387]
23/69 is about fashion
4 0
3 years ago
WILL MARK AS BRAINLIEST!!!!!!!!!!!!!!!
Nana76 [90]
(D.) It should be a bit less than 6 quarts (5.75 / 5 & 3/4 to be exact)
5 0
3 years ago
Read 2 more answers
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