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konstantin123 [22]

2 years ago

13

Im lazy dont ask please-

1 answer:

Helen [10]2 years ago

5 0

Answer:

0.75

or 3/4ths

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

Llana [10]

a) The given function is

$f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}$

The domain refers to all values of x for which the function is defined.

The function is defined for

$x^4+x^3-4x^2-4\ne0$

This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0

3 years ago

Which equation represents the sentence?

Sunny_sXe [5.5K]

<span>4x + 7 = 32
...................</span>

7 0

3 years ago

Adding and subtracing linear wxpressions 12(−4x+8)−14(8x−12)

Delicious77 [7]

Answer:

-160x+264

Step-by-step explanation:

-48+96x-112x+168

-160+264

3 0

3 years ago

George is drafting his dissertation paper for his doctoral program. The graph below shows the line of best fit for the data reco

sweet [91]

$a. \: y = \frac{3}{2} x + 4 \\ \\ 1. \: \frac{3}{2} x + 4 = y \\ \\ 2. \: \frac{3}{2} x = y - 4 \\ \\ 3. \: \frac{ \frac{3}{2} x}{\frac{3}{2} } = \frac{y - 4}{2} \\ \\ x = \frac{2y - 8}{3}$

3 0

3 years ago

Read 2 more answers

Help question attached multiple choice

Rina8888 [55]

ANSWER

$x = \frac{\pi}{2} , \frac{7\pi}{6} , \frac{3\pi}{2} , \frac{11\pi}{6}$

EXPLANATION

The given trigonometric equation is

$\cos(x) + 2 \cos(x) \sin(x) = 0$

We factor cos(x) to get:

$\cos(x) (1 + 2 \sin(x) ) = 0$

Apply the zero product property to obtain:

$\cos(x) = 0 \: or \: 1 + 2 \sin(x) = 0$

$\cos(x) = 0 \: or \: \sin(x) = - \frac{1}{2}$

Using the unit circle,

$\cos(x) = 0$

when

$x = \frac{\pi}{2}$

and

$x = \frac{3\pi}{2}$

We know

$\sin(y) = \frac{1}{2}$

when

$y= \frac{\pi}{6}$

The sine function is negative in the third and fourth quadrants.

$x = \pi + \frac{\pi}{6} = \frac{7\pi}{6}$

$x = 2\pi - \frac{\pi}{6} = \frac{11\pi}{6}$

Hence the solutions are:

$x = \frac{\pi}{2} , \frac{7\pi}{6} , \frac{3\pi}{2} , \frac{11\pi}{6}$

6 0

3 years ago