Round the following numbers to the nearest 10<br> a) 83<br> b) 127<br> c) 245

gulaghasi [49]

$\text{When you solve for absolute value, there could be two possible outcomes}\\\\\text{In this question, the outcomes could be:}\\\\-2x+4\geq4\\\text{or}\\\\-2x+4\geq-4\\\\\text{Solve:}\\\\\text{Possibility 1:}\\\\-2x+4\geq4\\\\\text{Subtract 4 from both sides}\\\\-2x\geq0\\\\\boxed{x\leq0}\\\\\text{Possibility 2:}\\\\-2x+4\geq-4\\\\-2x\geq-8\\\\\boxed{x\geq4}$

7 0

3 years ago

Listed below are measured amounts of caffeine? obtained in one can from each of 14 brands. Find the? range, variance, and standa

Makovka662 [10]

Answer:

00343434454151553647410053543804147

Step-by-step explanation:

6 0

3 years ago

10. A company finds that 45% of first-time visitors to its website do not buy any of its products. If there are 75 first-time vi

vekshin1

Using the binomial distribution, it is found that the probability that exactly 36 of them buy a product is of 0.044.

For each first-time visitor, there are only two possible outcomes, either they buy a product, or they do not. The probability of a first-time visitor buying a product is independent of any other first-time visitor, hence the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

45% of first-time visitors to its website do not buy any of its products, hence 55% buy, that is, p = 0.55.

There are 75 first-time visitors on a given day, hence n = 75.

The probability that exactly 36 of them buy a product is P(X = 36), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 36) = C_{75,36}.(0.55)^{36}.(0.45)^{39} = 0.044$

More can be learned about the binomial distribution at brainly.com/question/24863377

8 0

2 years ago

Select one answer choice For part A and select one answer choice for part B

sweet [91]

$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+6}x\stackrel{\stackrel{c}{\downarrow }}{+9}=0 ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{\underline{one real solution}}~~\textit{\Large \checkmark}\\ positive&\textit{two real solutions}\\ negative&\textit{no solution} \end{cases} \\\\\\ 6^2-4(1)(9)\implies 36-36\implies 0$