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Irina18 [472]
3 years ago
7

bsmiddle" class="latex-formula"> - \frac{2}{x-1} > 1
Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer:

Because i have no more information i assume you would like it to be solved.

x < -1 or -1/3 < x < 1

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<img src="https://tex.z-dn.net/?f=the%20%5C%3A%20angle%20%5C%3A%20of%20%5C%3A%20measure%20%5C%3A%20%20%5Cfrac%7B31%5Cpi%7D%7B6%7
Yakvenalex [24]

Answer:

3rd quadrant

Step-by-step explanation:

  • First we just convert the angle from radians to degrees
  • \frac{31\pi radians }{6}*\frac{180degrees}{\pi radians}  =\frac{31*180}{6} degrees=930degrees
  • Now that's too big, all this means is if we start rotating from the positive y-axis in a circle we will cross the starting point 2 times, 2 full circles;
  • 930degrees-360degrees=570degrees\\570degrees-360degrees=210degrees  
  • Now in which quadrant it 210 degrees?
  • 0 degrees to 90 degrees is 1st quadrant
  • 90 degrees to 180 degrees is 2nd quadrant
  • 180 degrees to 270 degrees is 3rd quadrant
  • 270 degrees to 360 degrees is 4th quadrant
  • So our answer is the 3rd quadrant.
7 0
2 years ago
Complete the following statements.
Charra [1.4K]

Answer:

1.) ax^2 + bx+ c =0

2.) parabola

3.) X=-b2a

4.) maximum

5.) minimum

Step-by-step explanation: hope this helps

4 0
3 years ago
Please need help fast. Look at the pictures.
Leya [2.2K]
It will definitely be a positive
5 0
3 years ago
2. Four friends share 3 apples equally.
Slav-nsk [51]

Answer:

1/3

Step-by-step explanation:

Each friend gets 1/3 of an apple

5 0
3 years ago
4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B
AleksAgata [21]

Answer:

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

Step-by-step explanation:

1) Data given and notation  

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

\hat p=\frac{63}{200}=0.315 estimated proportion of lawyers had used some form of advertising for their business

p_o=0.25 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

8 0
3 years ago
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