<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%2B1%7D" id="TexFormula1" title="\frac{x}{x+1}" alt="\frac{x}{x+1}" align="a

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Irina18 [472]

3 years ago

bsmiddle" class="latex-formula"> - $\frac{2}{x-1}$ > 1

Mathematics

1 answer:

navik [9.2K]3 years ago

4 0

Answer:

Because i have no more information i assume you would like it to be solved.

x < -1 or -1/3 < x < 1

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What is the solution to -x2 + 5x - 10 = 0?

Korolek [52]

Answer:

No solution

Explanation

−x^2+5x−10=0

Step 1: Use quadratic formula with a=-1, b=5, c=-10.

you plug it in as shown below

and simplify

when you simplify

you get

as shown below

This is no solution....

7 0

2 years ago

Need answer please !!

Misha Larkins [42]

Answer:

Step-by-step explanation:

Least common denominator is 10

there are 10/10 portions in the whole circle

1/2 = 5/10

2/5 = 4/10

10/10 - 5/10 - 4/10 = 1/10

3 0

2 years ago

Please show your work. The data modeled by the box plots represents the battery life of two different brand of batteries that Ji

Diano4ka-milaya [45]

(a) Brand X median = 13
Brand Y median = 16

Median is the center dot in the shaded box (in blue color). Look at the Time (h) axis for their values. For Brand X it is 13 whereas for the Brand Y it is 16

(b) If we compare their median values we can see that the difference is 3 hours (16-13 = 3). It means that the Brand Y battery will last longer compared to Brand X battery as Brand Y lasts for 16 hours whereas Brand X battery lasts for 13 hours.

7 0

3 years ago

Which is an integer that can be inserted on the blank line in the list? Negative 2.5 –2 Negative 1 and StartFraction 9 Over 10 E

bonufazy [111]

Answer:Negative 34, negative 2 and three-fourths, blank, negative 1.5, 0, 2.3, 10, 25 and one-fifth Which is an integer that can be inserted on the ...

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school

nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let $p_1$ = proportion of Illinois high school freshmen who have used anabolic steroids.

$p_2$ = proportion of Illinois high school seniors who have used anabolic steroids.

SO, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of high school freshmen who have used anabolic steroids = $\frac{34}{1679}$ = 0.0203

$\hat p_2$ = sample proportion of high school seniors who have used anabolic steroids = $\frac{24}{1366}$ = 0.0176

$n_1$ = sample of high school freshmen = 1679

$n_2$ = sample of high school seniors = 1366

So, the test statistics = $\frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }$

= 0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0

2 years ago