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3 years ago

The y-Int and the slope of C=7n+20 If you can show the formula

Mathematics

1 answer:

alisha [4.7K]3 years ago

8 0

I hope you understood!! :))

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Factor completely. 2x^2 – 15x + 7

KonstantinChe [14]

Answer:

(2x-1)(x-7)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone please explain how to do this

Nookie1986 [14]

Answer:

the mid point formula for this is x+x/2 and y+y/ 2 so #9would be 1/2, 3/2

7 0

3 years ago

you are studying for your final exam of the semester up to this point you received 3 exam scores of 96% 77% and 74% to receive a

il63 [147K]

The answer is 73<x<100 as seen from below.

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4 years ago

6 math geniuses help please!! math

damaskus [11]

Answer:

Step-by-step explanation:

Begin with Euler's formula. I am assuming youre aware of this if youre taking complex algebra? You can prove Euler's formula by doing a Maclaurin expansion of cosine, sine, and e^x. Euler's formula states that:

$e^{ix}=cos(x)+isin(x)$

We can put the first complex number in exponetial form by noticing the input is 2pi/3. The second complex number has an input of pi/3. Therefore:

$z_1=8e^{i(2\pi /3)}$

$z_2=0.5e^{i(\pi /3)}$

Then:

$\frac{z_1}{z_2} =\frac{8e^{i(2\pi /3)}}{0.5e^{i(\pi /3)}}$

Simplify the coefficients to get:

$\frac{z_1}{z_2} =\frac{16e^{i(2\pi /3)}}{e^{i(\pi /3)}}$

When you divide exponentials, you subtract the exponents. Therefore:

$\frac{z_1}{z_2} =16e^{i(2\pi /3)-i(\pi /3)}=16e^{i(\pi /3)$

Put it back into trigonemtric form using Euler's formula:

$16e^{i(\pi /3)}=16cos(\pi /3)+i16sin(\pi /3)$

Cosine of pi/3 is 0.5, and sine of pi/3 is square root of 3 over 2. We have:

$16e^{i(\pi /3)}=16cos(\pi /3)+i16sin(\pi /3)=16*0.5+16*\frac{\sqrt{3} }{2} *i=8+8\sqrt{3} i$

5 0

2 years ago

HELP PLEASE assume that y varies inversely with x. if y=1.6 when x=0.5 find x when y=3.2

DiKsa [7]

Y=k/x
1.6=k/0.5
K=0.8
Y=0.8/x
3.2=0.8/x
X=0.8/3.2
X=0.25
Hope this helps

4 0

4 years ago