Answer:
Hi, the general factorization formula, which will allow us to find the values for X of any polynomial of type Ах²⁺Вх+С.
Explanation:
This is one example taken from the C language:
int main()
{
int a,b,c,d;
float x,y;
printf("Input a: ");
scanf("%d",&a);
while (a == 0) {
printf("Input a: ");
scanf("%d",&a);
}
printf("Input b: ");
scanf("%d",&b);
printf("Input c: ");
scanf("%d",&c);
d = b*b-4*a*c;
if (d > 0) {
x = (-b+sqrt(d))/(2*a);
y = (-b-sqrt(d))/(2*a);
printf("x1 = %.2f\n",x);
printf("x2 = %.2f\n",y);
}
else if (d == 0) {
x = (-b)/(2*a);
printf("x1 = %.2f\n",x);
}
else
printf("The equation don't have solution.");
return 0;
}
Answer:
The class of language the machines recognise is Regular Language (See Explanation Below)
Explanation:
Given
Form δ : Q × Γ → Q × Γ × {R, S}
From the above transition form, it can be seen that the machine cannot read square symbols passed to it.
Regarding the square the machine is currently reading, there are multiple movement of S and it shouldn't be so because any number of the multiple movement can be simulated by exactly one movement of S.
As stated earlier that sequence of moves can be simulated by just one movement.
Let R = the movement
This means the machine can only use right move efficiently.
With this, we can say that the machine only read input string.
This is a characteristic of DFA (Deterministic Finite Automata).
With this, we can conclude that some DFAs will simulate the Turing machine and that they only read regular language.
Answer:
Explanation:
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