Answer:
dA/dt = k1(M-A) - k2(A)
Step-by-step explanation:
If M denote the total amount of the subject and A is the amount memorized, the amount that is left to be memorized is (M-A)
Then, we can write the sentence "the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized" as:
Rate Memorized = k1(M-A)
Where k1 is the constant of proportionality for the rate at which material is memorized.
At the same way, we can write the sentence: "the rate at which material is forgotten is proportional to the amount memorized" as:
Rate forgotten = k2(A)
Where k2 is the constant of proportionality for the rate at which material is forgotten.
Finally, the differential equation for the amount A(t) is equal to:
dA/dt = Rate Memorized - Rate Forgotten
dA/dt = k1(M-A) - k2(A)
A,E,F
Sq rt of 25 is 5 and 5 is less than 10
Sq rt of 36 is 6 and 6 is less than 10
Sq rt of 9 is 3 and 3 is less than 10
Answer:
A) (1,-2)
Step-by-step explanation:
the answer to a system of equations is where the 2 lines intersect and that would be at (1,-2)
Answer:
BCA = 65
Step-by-step explanation:
