A flat-creen tv costs $1,400.00. the tv is on sale for 35% off. what is the discounted price of the tv

Question 6

olga nikolaevna [1]

The answer to your question: 5 - 6t
why it’s saying for each number for 6 so what ever number times 6 is t

6 0

3 years ago

A student expressed the sum of 2 whole numbers as 5 times (8+3).What are the 2 whole numbers?

Marta_Voda [28]

Well if the two numbers are equal to 5x(8+3).

Lets say that these two numbers are X and Y,

So that would be X + Y = 5(8+3)

which means X + Y = 55

You could write that as a fuctions Y = 55 - X

Now by using the graph you get and the X values of [0,55] ( This means every value from 0 to 55 ), you will get a X and Y value that if you added up together will give you the value of 8(5+33)

An examples for the answers would be

(0,55) (1,54) (2,53) (3,52) (4,51) (5,50) (6,49) ... it goes on until x reaches 55.

8 0

3 years ago

A moving van changes a flat rate of $25 per day plus $0.12 per mile for every mile over 100 driven.If Millie’s bill was $29.46 h

Damm [24]

Answer: 137.17 miles

Step-by-step explanation: To know the driven miles, we will have to find the extra money paid divided by the unitary price of each driven mile.

Extra money=$29.46-$25=$4.46

Miles= $\frac{4.46}{0.12}$ =31.17 miles

However, this price per mile is only charged after 100 miles, therefore we will have to sum the extra miles driven and the 100 miles for the basis

Total=100 miles+31.17 miles=137.17

5 0

4 years ago

In the graph below, Point A represents Owen's house, Point B represents David's house and Point C represents the school. Who liv

ycow [4]

Answer:

• David

,

• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

,

• David's House, B(15,13)

,

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Owen's distance from school (AC)

$\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}$

David's distance from school (BC)

$\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}$

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding:

5 0

1 year ago

Please help i don’t understand

olganol [36]

9514 1404 393

Answer:

3

Step-by-step explanation:

Vertical angles share a vertex point, and have opposite rays for sides. In short, they are across the point of intersection from each other. Vertical angles do not have a common side (they are <em>not</em> adjacent).

The first part of the problem is to identify angle NCA. That is shown in red in the attachment. The vertical angle is across the point of intersection. It is angle 3.

5 0

3 years ago