Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
1. If the scale factor is k=6:13, then the ratio of their corresponding area is

;
2.

.

Solving for t:
Divide both sides by 52g:

Multiply both sides by -1:

Add 1 to both sides:

Multiply both sides by 100:
Answer: