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skelet666 [1.2K]
3 years ago
6

Does this parabola have a maximum or minimum value? y=-9(x-4)2-3

Mathematics
1 answer:
lara [203]3 years ago
5 0

Answer:

I think it is a maximum value.

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I agree that the article should not be used to the link to this page
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Select all statements that are true about the linear equation. y=−2x 4y=−2x 4 the point (0, 2)(0, 2) lies on the graph of the eq
Wittaler [7]
Y = -2x + 4

The graph of the equation is the set of points that are solutions to the equation.

The equation 2x + y = 4 is represented by the same graph.

For point (1, 2): 2 = -2(1) + 4 = -2 + 4 = 2.
Therefore, the point (1, 2) lies on the the graph of the equation.

For the point (0, 2): 2 ≠ -2(0) + 4 = 0 + 4 = 4.
Therefore, the point (0, 2) DOES NOT lie on the graph of the equation.
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3 years ago
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3 years ago
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Find the missing factor 6s^2-7s-5=(3s-5)()
victus00 [196]
Answer: 2s + 1


Explanation:

1) Given expression: 6s² - 7s- 5 = (3s - 5) (        )

2) The missing factor (     ) is such that when it is multiplied by (3s - 5) the product is 6s² - 7s- 5.

3) Since the first term of the first factor starts with 3s, the first term of the second factor shall be 2s (since they have to yield 6s²). Then, you can write:

6s² - 7s- 5 = (3s - 5) (2s +    )

4) The second term of the missing factor is positive because the product (+)(-) = (-) which is the sign of the third term of the polynomial.

5) The second term is such that when multiplied by - 5 is equal to the last term of the polynomial (also - 5), so this second terms is +1.

And you get: 6s² - 7s- 5 = (3s - 5) (2s +  1)

6) You can expand, using distributive property to confirm the result:

(3s - 5) (2s +  1 ) =  (3s)(2s)  + (3s)(1) - (5)(2s) -(5)(1) =  6s² - 7s- 5, which confirms the result.
3 0
3 years ago
What are the steps to this?
Nina [5.8K]

Answer:

20

Step-by-step explanation:

This is a right triangle

a² + b² = c²

16² + 12² = x²

256 + 144 = x²

400 = x²

take the square root of both sides

x = 20

3 0
3 years ago
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