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Lady bird [3.3K]

3 years ago

15

Can someone plzzzzz helppp

1 answer:

Ann [662]3 years ago

5 0

Y>(with the line underneath)1/3x-2 I think

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Math! Please give me the answer and EXPLAIN how you got it. (I need both)

Tomtit [17]

Answer:

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3 years ago

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Elenna [48]

I think the answer is 2/8..

7 0

4 years ago

Read 2 more answers

-2(x + 5) = -16 <br><br> = ???

34kurt

Answer:

if you're looking for x its -13

8 0

3 years ago

Read 2 more answers

Please help me with this Algebra I question.

horrorfan [7]

Answer:

$-\dfrac{b^2}{16a^4}$

Step-by-step explanation:

Given expression:

$\dfrac{(2a)^{-2}b^5}{-4a^2b^3}$

$\textsf{Apply the exponent rule}\quad (ab)^c=a^c \cdot b^c:$

$\implies \dfrac{2^{-2}a^{-2}b^5}{-4a^2b^3}$

Separate the variables:

$\implies \dfrac{2^{-2}}{-4}\cdot \dfrac{a^{-2}}{a^2}\cdot \dfrac{b^5}{b^3}$

$\textsf{Apply the exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies \dfrac{2^{-2}}{-4}\cdot a^{-2-2}\cdot b^{5-3}$

$\implies \dfrac{2^{-2}}{-4}\cdot a^{-4}\cdot b^{2}$

$\textsf{Apply the exponent rule}\quad a^{-n}=\dfrac{1}{a^n}:$

$\implies \dfrac{1}{-4(2^2)}\cdot \dfrac{1}{a^4}\cdot b^{2}$

$\implies -\dfrac{1}{16}\cdot \dfrac{1}{a^4}\cdot b^{2}$

Simplify:

$\implies -\dfrac{b^2}{16a^4}$

5 0

2 years ago

What would x equal for these two?<br> 15/24 = x/3 & 7/24 = 3/x<br><br> Thank you!!!

vesna_86 [32]

The first one you have $\frac{15}{24}$ = $\frac{x}{3}$ . To solve this you would multiply both sides by 3.

$\frac{45}{24}$ =x

Then simplify by dividing the numerator and denominator by 3.

$\frac{15}{8}$ =x (or in a mixed fraction 1 $\frac{7}{8}$ )

The second one you have $\frac{7}{24}$ = $\frac{3}{x}$ . To solve this you would multiply both sides by x.

$\frac{7}{24}$ x=3

Now you would divide both sides by $\frac{7}{24}$ .

x= $\frac{3}{\frac{7}{24}}$

You now then multiply 3 by 24 and then divide by 7.

$\frac{72}{7}$

x= $\frac{72}{7}$ (in a mixed fraction would be 10 $\frac{2}{7}$ )

6 0

3 years ago