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3 years ago

-2(x + 5) = -16 = ???

Mathematics

2 answers:

34kurt3 years ago

8 0

Answer:

if you're looking for x its -13

MaRussiya [10]3 years ago

6 0

Answer:

x = 3

Step-by-step explanation:

Given

-2(x + 5) = -16

Expand the bracket

-2 x X +-2 x 5 = 16

The positive sign changes to minus

-2x - 10 = -16

Add 10 to both sides

-2x -10 + 10 = -16 + 10

-2x = -6

Divide both sides by-2

x = -6/-2

x = 3

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Eddi Din [679]

Write down the Punnett square to find the frequencies:

R(.9) r(.1)
R 0.81 0.09
r 0.09 0.01

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7 0

3 years ago

Helpp!! I need to pass

goblinko [34]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Which of the following expressions is equal to g(x)?

Tatiana [17]

Answer:

Option D is right

Step-by-step explanation:

Given are two graphs. The first one is given as

$f(x) = log_{2} x\\$

The second one equation we have to find out.

Option A given as

$g(x) =\frac{1}{2} log_{2} x$ is having x intercept as

(0,1/2). But our g(x) has x intercept as 1. Hence not correct.

Option B: $g(x) = log_{2} \frac{1}{2} x$

This has x intercept as (0,2). Since does not match with g(x) not correct

OPtion C:

$g(x) = log_{2} 2x$

Here x intercept = 1 matches with ours.

Also g(2) = 2, twice as that of original f(x)

Hence option C is not right

Option D is only right because x intercept should be 1 and also when x=4 y=2(log 4 to base 2)

3 0

3 years ago

Read 2 more answers

The Highway Safety Department wants to study the driving habits of individuals. A sample of 37 cars traveling on a particular st

kodGreya [7K]

Answer:

90% confidence interval for the true mean speed of all cars on this particular stretch of highway is [68.9517 miles per hour , 72.4483 miles per hour].

Step-by-step explanation:

We are given that a sample of 37 cars traveling on a particular stretch of highway revealed an average speed of 70.7 miles per hour with a standard deviation of 6.3 miles per hour.

Firstly, the pivotal quantity for 90% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average speed of cars = 70.7 miles per hour

s = sample standard deviation = 6.3 miles per hour

n = sample of cars = 37

$\mu$ = true mean speed

Here for constructing 90% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.

So, 90% confidence interval for the true mean, $\mu$ is ;

P(-1.688 < $t_3_6$ < 1.688) = 0.90 {As the critical value of t at 36 degree of

freedom are -1.688 & 1.688 with P = 5%}

P(-1.688 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.688) = 0.90

P( $-1.688 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.688 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.688 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.688 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.688 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.688 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $70.7-1.688 \times {\frac{6.3}{\sqrt{37} } }$ , $70.7+1.688 \times {\frac{6.3}{\sqrt{37} } }$ ]

= [68.9517 miles per hour , 72.4483 miles per hour]

Therefore, 90% confidence interval for the true mean speed of all cars on this particular stretch of highway is [68.9517 miles per hour , 72.4483 miles per hour].

The interpretation of the above interval is that we are 90% confident that the true mean speed of all cars will lie between 68.9517 miles per hour and 72.4483 miles per hour.

8 0

3 years ago

Determine the number of outcomes in the event. Decide whether the event is a simple event or not. You randomly select one card f

Marat540 [252]

Answer:

No we can consider A as single event. See the explanation below

Step-by-step explanation:

Let's define the event A as:

A=" Select a 4 from a standard deck of 52 cards"

We know that in a standard deck we have 4 different types of 4, spade, heart, diamond and club.

And by definition of simple event we need to have just one possible outcome in the experiment, and on this case we have 4 possible options for event A, so for this reason the event A can't be considered as simpl event.

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4 years ago