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S_A_V [24]
3 years ago
10

Jabal and Michael are walking to school and agree to leave their homes at the same time.

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0

Answer: 6 seconds

Step-by-step explanation:

Time            Jabal (2.5mps)            Michael (5mps)

Start              15                                   0

1 sec              17.50                              5

2                    20                                  10

3                    22.5                               15

4                    25                                  20

5                    27.5                               25

6                    30                                  30

7

8

9

10

Ludmilka [50]3 years ago
6 0

Answer:

6 sec

Step-by-step explanation:

Let d = distance for Jabal

d + 15 = distance for Michael

t = d/r

d/2.5 = time for Jabal

(d + 15)/5 = time for Michael

The times are equal since they both started walking at the same time.

(d + 15/5 = d/2.5

2.5(d + 15) = 5d

2.5d + 37.5 = 5d

37.5 = 2.5d

d = 15 m. = Jabal's distance

15/2.5 = 6 sec.

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The slope and length of the given sides of the quadrilateral can be

found by using the coordinates of the vertices.

Correct responses:

  • Slope \ of \ \overline{IJ} = \underline{-\dfrac{7}{6} },      Length of \overline{IJ} = \underline{\sqrt{85} }
  • Slope \ of \ \overline{JK} = \underline {-\dfrac{2}{9}},     Length of \overline{JK} = \underline{\sqrt{85} }
  • Slope \ of \ \overline{KL} = \underline{-\dfrac{7}{6} },      Length of \overline{KL} = \underline{\sqrt{85}}
  • Slope \ of \  \overline{LI} = \underline{ -\dfrac{2}{9} },        Length of \overline{LI} = \underline{\sqrt{85} }

<h3>Methods used to find the slope and length of a line</h3>

The given coordinates of the vertices are;

K(-7, 0), J(2, -2), I(8, -9), L(-1, -7)

  • Slope = \mathbf{\dfrac{y_2 - y_1}{x_2 - x_1}}

  • Length \ of \ line =  \mathbf{ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}

Therefore;

Slope \ of \ \mathbf{\overline{IJ}} = \dfrac{-2 - (-9)}{2 - 8} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length \ of \ \mathbf{\overline{IJ}} = \sqrt{(2 - 8)^2 + (-2 - (-9))^2} = \underline{\sqrt{85}}

Slope \  of \ \mathbf{\overline{JK}} = \dfrac{0 - (-2)}{-7 - 2}  = \dfrac{2}{-9} = \underline{-\dfrac{2}{9}}

Length \ of \ \mathbf{\overline{JK}} = \sqrt{(-7 - 2)^2 + (0 - (-2))^2}  = \underline{ \sqrt{85}}

Slope \ of \ \mathbf{\overline{KL}} = \dfrac{0 - (-7)}{-7 - (-1)} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length  \ of \ \mathbf{\overline{KL} }= \sqrt{(-7 - (-1))^2 + (0 - (-7))^2} =\underline{ \sqrt{85}}

Slope \ of \ \mathbf{\overline{LI}} = \dfrac{(-9 - (-7))}{(8 - (-1))} = \dfrac{-2}{9} = \underline{-\dfrac{2}{9}}

Length \ of \ \mathbf{\overline{LI}} = \sqrt{(8 - (-1))^2 + (-9 - (-7))^2} = \underline{\sqrt{85}}

Learn more about finding the slope and length of a line here:

brainly.com/question/11612395

brainly.com/question/14039630

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