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Otrada [13]
3 years ago
7

Plankton are classified based on their size. There are different types of plankton, such as megaplankton, mesoplankton, and femt

oplankton. Femtoplankton can be as small as 2 × 10-8 meter. Mesoplankton can be up to 1 × 106 times bigger than femtoplankton. Megaplankton, such as jellyfish, can have a diameter 1 × 108 times the size of the smallest femtoplankton.
question 2
part a:
Write an expression to find size of the largest jellyfish. Represent the expression in meters as a product of two numbers in scientific notation.

part b:
Apply the Commutative and Associative Properties of multiplication to the expression you found in part A.

Part c:
Now that the first factors are grouped and the powers of 10s are grouped, multiply the first factors in the expression from part B. Then multiply the powers of 10 by using the properties of exponents.

part d:
Make sure the expression that you found in part C is in scientific notation. Using scientific notation, represent the size of the largest jellyfish in meters. If the exponent is 0, you can leave out the term containing the power of 10.
Mathematics
2 answers:
asambeis [7]3 years ago
8 0

Answer:

Part A

A jellyfish can be up to 1 × 10^8 times bigger than femtoplankton. Find the size of the largest jellyfish by multiplying the size of a femtoplankton by 1 × 10^8 times.

The size of a femtoplankton is 2 × 10^-8 meter. That means the expression for the size of the largest jellyfish 1 × 10^8 • 2 × 10^-8 meters.

Step-by-step explanation:

Sample Answer from Edmentum,

Dvinal [7]3 years ago
4 0

Answer:

Part A:

A jellyfish can be up to 1 × 10^8 times bigger than femtoplankton. Find the size of the largest jellyfish by multiplying the size of a femtoplankton by 1 × 10^8 times.

The size of a femtoplankton is 2 × 10^-8 meter. That means the expression for the size of the largest jellyfish 1 × 10^8 • 2 × 10^-8 meters.

Part B:

The expression from part A is 1 × 10^8 • 2 × 10^-8.

Apply the Commutative and Associative Properties of multiplication to get

1 × 10^8 • 2 × 10^-8  

= 1 • 10^8 • 2 • 10^-8       (using the Associative Property)

= 1 • 2 • 10^8 • 10^-8        (using the Commutative Property)

= (1 • 2) • (10^8 • 10^-8)       (using the Associative Property)

Part C:

The expression from part B is (1 • 2) • (10^8 • 10^-8).

Multiply the first factors.

1 • 2 = 2

Multiply the powers of 10 using the properties of exponents, a^n a^m = a^n + ^m.

10^8 • 10^-8 = 10^8 + (^-8) = 100

The expression is 2 × 10^0.

Part D:

The expression from part C is 2 × 10^0.

Because 10^0 = 1, leave out the power of 10.

The size of the largest jellyfish is 2 meters.

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X<br> 8<br> 17<br> Find the exact value of x.<br> X=
Furkat [3]

Answer:

621

629

Step-by-step explanation:

We know that

sin

(

x

+

y

)

=

sin

x

cos

y

+

sin

y

cos

x

If

cos

x

=

8

17

and

sin

y

=

12

37

We can use,

cos

2

x

+

sin

2

x

=

1

and

cos

2

y

+

sin

2

y

=

1

To calculate

sin

x

and

cos

y

sin

2

x

=

1

−

cos

2

x

=

1

−

(

8

17

)

2

=

225

17

2

sin

x

=

15

17

cos

2

y

=

1

−

sin

2

y

=

1

−

(

12

37

)

2

=

1225

37

2

cos

y

=

35

37

so,

sin

(

x

+

y

)

=

15

17

⋅

35

37

+

12

37

⋅

8

17

=

621

629

Answer link

Shwetank Mauria

Nov 22, 2016

sin

(

x

+

y

)

=

621

629

or

−

429

629

depending on the quadrant in which sine and cosine lie.

Explanation:

Before we commence further, it may be mentioned that as

cos

x

=

8

17

,

x

is in

Q

1

or

Q

4

i.e.

sin

x

could be positive or negative and as

sin

y

=

12

37

,

y

is in

Q

1

or

Q

2

i.e.

cos

y

could be positive or negative.

Hence four combinations for

(

x

+

y

)

are there and for

sin

(

x

+

y

)

=

sin

x

cos

y

+

cos

x

sin

y

, there are four possibilities.

Now as

cos

x

=

8

17

,

sin

x

=

√

1

−

(

8

17

)

2

=

√

1

−

64

289

=

√

225

289

=

±

15

17

and

as

sin

y

=

12

37

,

cos

y

=

√

1

−

(

12

37

)

2

=

√

1

−

144

1369

=

√

1225

1369

=

±

35

37

Hence,

(1) when

x

and

y

are in

Q

1

sin

(

x

+

y

)

=

15

17

×

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(2) when

x

is in

Q

1

and

y

is in

Q

2

sin

(

x

+

y

)

=

15

17

×

−

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

(3) when

x

is in

Q

4

and

y

is in

Q

2

sin

(

x

+

y

)

=

−

15

17

×

−

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(4) when

x

is in

Q

4

and

y

is in

Q

1

sin

(

x

+

y

)

=

−

15

17

×

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

Hence,

sin

(

x

+

y

)

=

621

629

or

−

429

629

7 0
3 years ago
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