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2 years ago

Please help me ill mark you as brainiset

Mathematics

1 answer:

Artyom0805 [142]2 years ago

8 0

Answer: -$560

Step-by-step explanation: Ahem, So basically u divide -$5040 by 9 months and then you get -$560

Plz mark me brainliest it would mean so much! :)

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Draw a rectangle that has an area of 8 square units and a perimeter of 12 units. What are the side lengths of the rectangle?

Alex73 [517]

Perimeter = 12
2(w+l) = 12
w + l = 6

area = 8
w x l = 8

the possibility
length = 4
width = 2

i know you can draw it

5 0

3 years ago

Read 2 more answers

Please help

tigry1 [53]

Just plug in the x-values into the given equation to find. For 9-19-19 whatever the number is correlated to how much the graph is being moved down or up and the x is your slope.

5 0

2 years ago

(x+2)^2+(x-3)^2-2x^2)

garri49 [273]

Answer:

13 - 2x

Step-by-step explanation:

(x +2)² + (x - 3)² - 2x²

Expand.

(x + 2)(x + 2) + (x - 3)(x - 3) - 2x²

x² + 2x + 2x + 4 + x² - 3x - 3x + 9 - 2x²

Bring all the like terms together then simply.

x² + x² - 2x² + 2x + 2x - 3x - 3x + 4 + 9

2x² - 2x² + 4x - 6x + 13

= 13 - 2x (or -2x + 13 )

4 0

2 years ago

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.f(x) = 3x3 + 39x2 + 39x + 27

kramer

First, we can factor this to make it easier to solve:

3(x^3 + 13x^2 + 13x + 9)

Now, we can use the rational root theorem like so:

List factors of 9:

1, 3, 9.

List factors of 1:

Because of this, we know our possible rational roots are:

+/-1, +/-3, +/-9

If none of these zeros fit using the remainder theorem, then we know our roots will be irrational.

8 0

2 years ago

Mrs. Del Pup bought 20 yards of border for her classroom bulletin board.

KengaRu [80]

A rectangle with dimensions $x$ and $y$ has perimeter 20 if

$2(x+y)=20 \iff x+y=10$

and we can deduce

$y=10-x$

So, the dimensions of the rectangle must be $x$ and $10-x$ , where x ranges from 0 to 10 (both extremes are excluded, otherwise you'd have a degenerate rectangle, which is actually a segment).

So, all the possible areas are given by the product of the dimensions, i.e.

$x(10-x) = -x^2+10x$

The function $f(x)=-x^2+10x$ represents a parabola, facing downwards, and thus it admits a maximum, which is its vertex.

In particular, the vertex of this parabola is given by

$x=\dfrac{-b}{2a}=\dfrac{-10}{-2}=5$

And it yields an area of

$f(5)=-25+50=25$

(a) So, she can frame a maximum area of 25 squared yards.

(b)The dimensions of the rectangle with greatest area are $x=5$ and $y=10-x=10-5=5$ , so it's actually a square.

This is a well known theorem: if you fix the perimeter, the rectangle with the largest area is the square yielding that perimeter.

(c) If we increase both dimensions by 2 yards, our 5x5 square would become a 7x7 square...

(d) ...and the new area would be $7^2=49$ squared yards. So, the new area is $49-25=26$ squared yeards more than the old one.

6 0

2 years ago