Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
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Answer: 567
Step-by-step explanation: cause im smart i think
Answer:
99+3b
Step-by-step explanation:
The original equation would be 3(33+b), but simplifying it would get 99+3b.
10x + 2y - 6 = 0
Multiply 5x + y - 3 = 0 by 2
2(5x + y - 3 = 0) = 10x + 2y - 6 = 0
Answer:
B -27
Step-by-step explanation:
7(-5)+ 6(2)-4
-35 +12-4
-23-4
-27
