Using the figure below, solve for Y.

Leo multiplied all numbers from 1 to 11 and wrote the answer on the board. During the break three digits were erased 39,9...6,8.

Pavlova-9 [17]

11! = 39,916,800

The erased digits are 1, 0, 0.

6 0

3 years ago

What is the order of operations for evaluating expressions

Phantasy [73]

PEMDAS!

Parenthesis
Exponents
Multiplication
Division
Adding
Subtracting

8 0

3 years ago

Read 2 more answers

A firm has a beta of 1.3 and a debt-to-equity ratio of .4. The market rate of return is 11.6

Citrus2011 [14]

Beta= 1.3

Debt to equity ratio= 0.4

Market rate of return= 11.6%

= 11.6/100

= 0.116

Tax rate= 32%

= 32/100

= 0.32

Risk free rate= 3.3%

= 3.3/100

= 0.033

Pretax cost of debt= 7.2%

= 7.2/100

= 0.072

The firm's WACC can be calacluated as follows

RS= 0.033+1.3(0.116-0.033)

= 0.033+1.3(0.083)

= 0.033+0.1079

= 0.1409

WACC= (1/1.4)(0.1409)+(2/1.4) (0.072)(1-0.32)

= (0.7142)(0.1409) + (1.4285)(0.072)(0.68)

= 0.1006+0.0699

= 0.1705(100)

= 17.05%

Hence the firm's WACC is 17.05%

6 0

3 years ago

A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed

Natali [406]

Answer:

$t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587$

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a one sided test the p value would be:

$p_v =P(t_{(14)}>2.587)=0.0108$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

Step-by-step explanation:

Data given and notation

$\bar X_{1}=1.17$ represent the mean for the sample 1 (25 mil film)

$\bar X_{2}=1.04$ represent the mean for the sample 2 (20 mil film)

$s_{1}=0.11$ represent the sample standard deviation for the sample 1

$s_{2}=0.09$ represent the sample standard deviation for the sample 2

$n_{1}=8$ sample size selected for 1

$n_{2}=8$ sample size selected for 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if reducing the film thickness increases the mean speed of the film, the system of hypothesis would be:

Null hypothesis: $\mu_{1} \leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a one sided test the p value would be:

$p_v =P(t_{(14)}>2.587)=0.0108$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

4 0

3 years ago

I am a bit lost with this problem. Could someone please explain this to me :)

Serjik [45]

They want the point D such that D is equally distant away from the three gates. Call the gates A, B, and C

They want
AD = BD = CD

If we draw a circle through those three points, then point D would be the center
This circle is known as the circumcircle as it goes through the three points
The center D is the circumcenter

So all you have to do is find the perpendicular bisector of two segments of the triangle, say of AB and BC. Then find where those perpendicular bisectors meet. That intersection would be point D.

Since we don't have actual numbers or coordinates to work with, we can't go further and actually find out where point D is located in terms of (x,y) coordinates. However, you can still get a good idea using a compass and straightedge.

3 0

3 years ago