Width 2x-5 hope this helped
Answer:
y = 1/3x -1
Step-by-step explanation:
We have 2 points (9,2) and (42,13)
We can find the slope
m = (y2-y1)/(x2-x1)
= (13-2)/(42-9)
=11/33
=1/3
The slope is 1/3
We can use the point slope form of the equation
y-y1 = m(x-x1)
y-2 = 1/3(x-9)
Distribute
y-2 = 1/3x -3
Add 2 to each side
y-2+2 = 1/3 x-3+2
y = 1/3x -1
-1/8 -2/8 -3/8 because any fraction is ok, they don't have 0 as a denominator.
Answer:
3 dogs and 5 cats were adopted out on Christmas eve.
Step-by-step explanation:
Let the number of dogs adopted out on Christmas eve be x and the number of cats be y.
From the question,
On Christmas Eve, the animal adopted out 8 total animals
That is, x + y = 8 ...... (1)
and brought in $400 in total adoption fees.
Also from the question,
Each dog adoption fee was $75 and each cat adoption fee was $35.
∴ On Christmas Eve,
75x + 35y = 400 ...... (2)
Now, to determine how many dogs and how many cats were adopted out on Christmas Eve, we will solve the two equations simultaneously.
From equation (1)
x + y = 8
Make x the subject of the relation.
∴ x = 8 - y ...... (3)
Substitute the value of x into equation (2)
75(8 - y) + 35y = 400
600 - 75y + 35y = 400
600 -40y = 400
600 - 400 = 40y
200 = 40y
∴ 40y = 200
y = 200/40
y = 5
Substitute the value of y into equation (3)
x = 8 - y
x = 8 - 5
x = 3
∴ x = 3 and y = 5
Hence, 3 dogs and 5 cats were adopted out on Christmas eve.
Answer:
(16 x^8 - x^3 + 6)/(2 x^3)
Step-by-step explanation:
Simplify the following:
(64 x^8 - 4 x^3 + 24)/(8 x^3)
Factor 4 out of 64 x^8 - 4 x^3 + 24:
(4 (16 x^8 - x^3 + 6))/(8 x^3)
4/8 = 4/(4×2) = 1/2:
Answer: (16 x^8 - x^3 + 6)/(2 x^3)
