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Aleksandr [31]
3 years ago
9

The animal shelter had a special on adoption rates for their dogs and cats. Each dog adoption fee was $75 and each cat adoption

fee was $35. On Christmas Eve, the animal adopted out 8 total animals and brought in $400 in total adoption fees. How many dogs and how many cats were adopted out on Christmas Eve?
dogs:

cats:
Mathematics
1 answer:
lidiya [134]3 years ago
4 0

Answer:

3 dogs and 5 cats were adopted out on Christmas eve.

Step-by-step explanation:

Let the number of dogs adopted out on Christmas eve be x and the number of cats be y.

From the question,

On Christmas Eve, the animal adopted out 8 total animals

That is, x + y = 8 ...... (1)

and brought in $400 in total adoption fees.

Also from the question,

Each dog adoption fee was $75 and each cat adoption fee was $35.

∴ On Christmas Eve,

75x + 35y = 400 ...... (2)

Now, to determine how many dogs and how many cats were adopted out on Christmas Eve, we will solve the two equations simultaneously.

From equation (1)

x + y = 8

Make x the subject of the relation.

∴ x = 8 - y ...... (3)

Substitute the value of x into equation (2)

75(8 - y) + 35y = 400

600 - 75y + 35y = 400

600 -40y = 400

600 - 400 = 40y

200 = 40y

∴ 40y = 200

y = 200/40

y = 5

Substitute the value of y into equation (3)

x = 8 - y

x = 8 - 5

x = 3

∴ x = 3 and y = 5

Hence, 3 dogs and 5 cats were adopted out on Christmas eve.

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4 years ago
Jake forgot to replace the cap on a bottle of deodorant. The deodorant began to evaporate at the rate of 12% per day. If the ori
belka [17]

Answer:

graph of function f of x equals 30 multiplied by 0.88 to the power of x

Step-by-step explanation:

The deodorant is begun to evaporate in other words, it is losing mass so the rate of 12% is a decay rate.  In the exponential decay, the graph of the function goes according to the formula:

y=a(1-r)^x

Where a is the initial amount (a=30), r is the rate of decay (r=0.12) and x the times intervals, in this case, measured in days. Substituting the values in the formula:

y=30(1-0.12)^x\\y=30(0.88)^x

Which corresponds with the "graph of function f of x equals 30 multiplied by 0.88 to the power of x".

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A bag contains purple marbles and red marbles, 34 in total. The number of purple marbles is 2 more than 3 times the number of re
Irina-Kira [14]

Answer:

There are 26 purple marbles in the bag.

Step-by-step explanation:

Firstly, you have to make an expression in terms of x where x represent red marbles. Given that the question says purple marbles is 2 more than 3 times the number of red marbles. So the expression is :

Let red marbles = x,

purple = 2 + 3x

red = x

Next, given that the total marbles in the bag is 34 so you have to add both marbles together and solve the value of x :

2 + 3x + x = 34

4x = 32

x = 32 \div 4

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Lastly, you have to substitute the value of x into the expression of purple marbles :

Let x = 8,

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Answer:

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