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aliina [53]
3 years ago
12

Start at 2 Create a pattern that adds 2 to each number and then multiply by three. Stop when you have a five numbers​

Mathematics
2 answers:
puteri [66]3 years ago
4 0

Answer:

2,12,42,132,402

Step-by-step explanation:

NeTakaya3 years ago
3 0

Answer:

2,4,12,36,108

Step-by-step explanation:

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PLS HELP ASAP ILL GIVE BRAINLKEST PLS THANKSS
Ilya [14]

Answer:

1. y=x+9

2. y=x+8

6 0
3 years ago
Read 2 more answers
Which of the following shows the correct order for -1 2/5 , (-1)2 , -1.4 , and (1/2)2?
Brut [27]
The order of these numbers from smallest to largest is:

(-1)2, -1 2/5, -1.4, (1/2)2


-1 2/5 and -1.4 are technically the same, though.
5 0
3 years ago
In simplest form …..
777dan777 [17]

Answer:

2\sqrt[3]{2}    

Step-by-step explanation:

\sqrt[3]{54} - \sqrt[3]{2}

\sqrt[3]{2 * 3 * 3 * 3} - \sqrt[3]{2}         Prime factorization.

3\sqrt[3]{2} - \sqrt[3]{2}                      Simplify the radical.

2\sqrt[3]{2}                              Subtract.

8 0
3 years ago
Help!!!! Quick and easy!
ELEN [110]
Make an equation
6p + p = 28
Combine like terms
7p = 28
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Solution: p = 4
4 0
3 years ago
Suppose we want to choose 3 objects, without replacement, from the 4 objects pencil, eraser, desk, and chair.
Crank

Answer:

4 ways of choosing

Step-by-step explanation:

If you want to choose 3 objects, without replacement, from the 4 objects which are distinct, then permutation i.e then their arrangement doesn't really matter. Only their combination will be considered

That means, order of choosing doesn't matter,

pencil/ eraser/ desk will be same as  eraser/ desk/ pencil.

Number of ways of selecting 3 objects out of 4 distinct objects is:

⁴C₃ = \frac{4 !}{3! \times (4-3)!}

⁴C₃ = \frac{4 \times 3 \times 2 \times 1}{3 \times 2 \times 1}

⁴C₃ = 4

So, there are 4 ways of choosing

5 0
4 years ago
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