The dimensions i.e. length and width of the deck in the drawing is 8 and 6.4 inches respectively.
Given that the length of the previous deck = 15 feet
The width of the previous deck = 12 feet
Since the new deck will add 5 feet to the length and 4 feet to the width,
The length of the new deck = 15 + 5 = 20 feet
The width of the new deck = 12 + 4 = 16 feet
Also given that a drawing of the new deck uses a scale of 1 inch = 2.5 feet.
So, The length of the deck in the drawing = 20/2.5 inches = 8 inches
The width of the deck in the drawing = 16/2.5 inches = 6.4 inches
Therefore, the dimensions i.e. length and width of the deck in the drawing is 8 and 6.4 inches respectively.
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Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
X = 75% * y
Where 'x' is the single tennis court width, and 'y' is the doubles tennis court width.
Plug in what we know:
27 = 75% * y
75% = 0.75
27 = 0.75 * y
27 = 0.75y
Divide 0.75 to both sides:
y = 36
So the doubles court is 36 feet wide.
Waist to Hip Ratio (WHR) = Waist Measurement / Hip Measurement
Waist Measurement = 40 inches
Hip Measurement = 2 inches less = (40 -2) = 38 inches.
Waist to Hip Ratio (WHR) = 40/38 = 1.0526
Answer:
41 and 77
Step-by-step explanation:
x: his age the first time he went to space
y: his age the second time he went to space
the second time he went to space he was 5 years younger than twice the age when he went his first time, then:
y = 2x - 5
the sum of both ages is 118, then:
x + y = 118
If you replace y = 2x - 5 in x + y =118:
x + 2x - 5 = 118
3x = 123
x = 41
replacing x:
41 + y = 118
y = 118 - 41
y = 77
so when he was 77, he was 5 years younger than twice 41 ( 41*2 = 82 => 82 - 5 =77)
