Answer:
Option C
Explanation:
Let the allele for black color be "B"
and the allele for white color be "b"
Since after F1 generation all the offspring have black body with white speckles throughout their feathers.
Thus the allele for black and white show co dominance.
Genotype of parent after F1 generation would be Bb for speckled chickens
Cross between two specked adults will produce -
Bb x Bb
BB, Bb, Bb, bb
Out of four offspring 1 is black (BB), 1 is white (bb) and two are speckled (Bb)
Thus 50% of the offspring will be speckled, 25% will be black, and 25% will be white.
Option C is correct
Guessing it’s D. Hope this was helpful!
Black fur in mice (B) is dominant to brown fur (b). Short tails (T) are dominant to long tails (t). (C) 1 / 2 of the progeny of crosses Bb Tt × BB tt will be expected to have black fur and long tails.
Crosses among individuals differing in two traits is known as a dihybrid cross.
Mice with genotype Bb Tt will form 4 types of gametes, namely, BT, Bt, bT and bt, while those containing the genotype BB tt will produce gametes with 'Bt' combination.
On crossing Bb Tt × BB tt, we will get 16 possible genotypes. However, only 8 offspring will have black fur (B) and long tails (t) with the possible genotypes- BBtt and Bbtt.
Thus, on dividing 8 by 16 we get 1/2.
To learn more about dihybrid cross here
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Answer:
permeability
Explanation:
dictionary definition: the state/quality of a material or membrane that causes it to allow liquids or gases to pass through it
in biology we use this term to describe the cell membrane, it is "semi-permeable" because it allows certain gasses and molecules to pass through
Answer:
Metamorphic rocks develop when heat and pressure convert an existing rock into a new rock. Contact metamorphism transpires when hot magma converts the rock that it contacts. Regional metamorphism remodels large areas of existing rocks under the enormous heat and pressure created by tectonic forces.
Explanation:
