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White raven [17]
3 years ago
7

15. Enter an angle that is vertical with /_ AXD in the diagram below:

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

i guess /_CXB

Step-by-step explanation:

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The heart rate of 10 adults is measured and the results are 83, 87, 90, 92, 93, 100, 104, 111, 115, 121. Find the interquartile
zloy xaker [14]

The interquartile range of the data set is 21.

Given that the heart rate of 10 adults is measured and the results are 83, 87, 90, 92, 93, 100, 104, 111, 115, 121.

The interquartile range shows the extent of the middle half of the distribution. Quartiles segment any distribution, ordered from low to high, into four equal parts. The interquartile range (IQR) contains the second and third interquartile ranges, the central half of the dataset.

The value of quartile 1 is Q₁=90

The value of quartile 3 is Q₃=111

So, the interquartile range is

IQR=Q₃-Q₁

IQR=111-90

IQR=21

Hence, the interquartile range of the data set 83, 87, 90, 92, 93, 100, 104, 111, 115, 121 is 21.

Learn more about the interquartile range from here brainly.com/qustion/18723655

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6 0
2 years ago
At a certain time of day, a 5 foot tall man has an 8 foot shadow. If a tree is 20 feet tall, what is the distance between the tr
Leto [7]
If they're asking the distance between the tree and the man's shadow, that would be 12ft and if they're asking the distance between the tree and the actually man, that would be 15ft :).
5 0
3 years ago
jayla made five more sales calls than clark. jayla and clark made a total of 33 sales calls. how many sales calls did each make?
Anni [7]

Answer:

14 each

Step-by-step explanation:

33-5=29

28/2=14

14 each

5 0
3 years ago
A bag contains eleven equally sized marbles, which are numbered. Two marbles are chosen at random and replaced after each select
Digiron [165]

Answer:

B. \frac{24}{121}.

Step-by-step explanation:

Total number of marbles = 11.

Since, after choosing the first marble, we are putting it back and then the second marble is chosen.

As, there are 4 shaded marbles.

So, the probability of getting the first marble shaded = \frac{\binom{4}{1}}{\binom{11}{1}} = \frac{4}{11}

Also, there are 6 odd labeled marbles.

So, the probability of getting the second marble being odd labeled = \frac{\binom{6}{1}}{\binom{11}{1}} = \frac{6}{11}

So, the probability of getting the first marble shaded and second marble labeled odd = \frac{4}{11}\times \frac{6}{11} = \frac{24}{121}.

Hence, the required probability is \frac{24}{121}.

4 0
3 years ago
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Please help me, I am lost from 3.2 going down
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