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2 years ago

15. Enter an angle that is vertical with /_ AXD in the diagram below:

Mathematics

1 answer:

scoundrel [369]2 years ago

3 0

Answer:

i guess /_CXB

Step-by-step explanation:

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In rectangle ABCD the diagonals intersect each other at point O and m∠ABD = 30°. Find BC if AC = 16 in

pashok25 [27]

16(sin 30degrees) = BC

BC = 8

4 0

3 years ago

Read 2 more answers

A 42-inch board is to be cut into three pieces so that the second piece is twice as long as the first piece and the third piece

Karo-lina-s [1.5K]

Answer: 7 inches

Step-by-step explanation:

If x is the first piece, and the second piece is twice as long, then the second piece is 2x.

If the third piece is three times as long as the first piece, x, then the third piece is 3x.

The 42-inch board must be equal to all 3 pieces, so we will set up an equation and solve for x.

42 = x + 2x + 3x

42 = 6x

7 = x

The first piece is 7 inches long.

Learn more about your question here: brainly.com/question/20320071

5 0

1 year ago

Mental Math A typical tip in a restaurant is 15% of the total bill. If the bill is $120, what would the typical tip be? The typi

pychu [463]

Answer:

18 dollars and zero cents

Step-by-step explanation:

120×15%

4 0

2 years ago

Read 2 more answers

Pablo's retirement party will cost $8 if he invites 4 guests. If there are 6 guests, how

mezya [45]

Answer:

$12

Step-by-step explanation:

Step 1:

$8 : 4 = x : 6

Step 2:

4x = 48

Answer:

x = 12

Hope This Helps :)

6 0

3 years ago

A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?

seraphim [82]

Answer:

$P\left(E\right)=\frac{55}{1024}$

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

$nCr=\frac{n!}{r!\left(n-r\right)!}$

Plug in n = 12 and r = 9

$=\frac{12!}{9!\left(12-9\right)!}$

$=\frac{12!}{9!\cdot \:3!}$

$=\frac{12\cdot \:11\cdot \:10}{3!}$ ∵ $\frac{12!}{9!}=12\cdot \:11\cdot \:10$

$=\frac{1320}{6}$ ∵ $3!\:=\:3\times 2\times 1=6$

$=220$

Thus, the probability will be:

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

$=\frac{220}{4096}$

$=\frac{55}{1024}$

Thus, the probability of the coin landing tails up exactly nine times will be:

$P\left(E\right)=\frac{55}{1024}$

4 0

2 years ago