Answer:
Simplifying
T = C(9 + AB) * forB
Reorder the terms for easier multiplication:
T = C * forB(9 + AB)
Multiply C * forB
T = forBC(9 + AB)
T = (9 * forBC + AB * forBC)
Reorder the terms:
T = (forAB2C + 9forBC)
T = (forAB2C + 9forBC)
Solving
T = forAB2C + 9forBC
Solving for variable 'T'.
Move all terms containing T to the left, all other terms to the right.
Simplifying
T = forAB2C + 9forBC
Step-by-step explanation:
Simplifying
T = C(9 + AB) * forB
Reorder the terms for easier multiplication:
T = C * forB(9 + AB)
Multiply C * forB
T = forBC(9 + AB)
T = (9 * forBC + AB * forBC)
Reorder the terms:
9 on the top as well so 9 x 2 18 3x2 6 3
Answer:
7t^2 + 21t
Step-by-step explanation:
You have 7 tiles of each t by t+3.
One tile has an area of
t * (t+3) = t^2 + 3t
So in total the area is
7* (t^2 + 3t)
7t^2 + 21t
Answer:
The first option is the correct one, the area of the shaded portion of the circle is
[/tex](5 \pi -11.6)ft^2[/tex]
Step-by-step explanation:
Let us first consider the triangle + the shadow.
The full area of the circle is the radius squared times pi, so
A=
Since 
, the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus
If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from 
.
The area of the triangle is given by
Thus the area of the shaded portion of the circle is
