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Ksenya-84 [330]

3 years ago

6

Graph the following features: Slope = 1/3 Y-intercept = 3

2 answers:

nika2105 [10]3 years ago

7 0

Answer:

If it doesn't show, use desmos graphing, it'll help you.

malfutka [58]3 years ago

5 0

Answer:

The answer is in the photo.

Step-by-step explanation:

Start by putting a dot on (0,3). Then go up one and to the right three, and that will be your next dot and then just go from there and keep going up one and to the right three. Then to get the other half of your graph you will do the opposite by going down one and to the left three.

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4. Which of these non-terminating decimals can be converted into a rational number? A. 0.874387438743... B. 0.0000100020003... C

Umnica [9.8K]

Answer: A. 0.874387438743.. is a rational number.

Step-by-step explanation:

Since Any number that can be written in fraction form is a rational number if it can be in the form of p/q where p and q are integers and q≠0

Since we can write 0.874387438743... = $\frac{8743}{9999}$

Where, 8743 and 9999 are integers and 9999≠0

Thus, 0.874387438743... is a rational number.

But, 0.0000100020003... , 5.891420975..... and 10.07401259... can not be written in the form of p/q therefore they are not the rational number.

Therefore, Only Option A is correct.

6 0

3 years ago

A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i

Setler79 [48]

Answer:

Part a) The slant height is $3\sqrt{2}\ units$

Part b) The lateral area is equal to $54\sqrt{2}\ units^{2}$

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

so

$LA=6[\frac{1}{2}(b)(l)]$

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

$l^{2}=h^{2} +a^{2}$

where

h is the height of the pyramid

a is the apothem

we have

$h=3\ units$

$a=3\ units$

substitute

$l^{2}=3^{2} +3^{2}$

$l^{2}=18$

$l=3\sqrt{2}\ units$

Part b) Find the lateral area

$LA=6[\frac{1}{2}(b)(l)]$

we have

$b=6\ units$

$l=3\sqrt{2}\ units$

substitute the values

$LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}$

3 0

3 years ago

Read 2 more answers

Complete the congruence statement

Dvinal [7]

Angle Y equals Angle S

8 0

3 years ago

3/8 + -7/8 ???????????

saw5 [17]

Answer:

-0.5 hope this help

Step-by-step explanation:

3 0

3 years ago

Keith_Richards [23]

Answer:

a

Step-by-step explanation:

8 0

3 years ago