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2 years ago

What is the least common multiple of 4 and 8? Enter your answer in the box.

Mathematics

1 answer:

jeyben [28]2 years ago

7 0

Answer:

The least common would be 8

Step-by-step explanation:

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How do you simplify 12 + 15 ÷ 3 × 6 – 4 step by step?

tatuchka [14]

Seperate the questions 12+15=25 ÷ by 3×6= 18-4= the answer

6 0

2 years ago

Solve by completing the square. x^2 + 4x – 1= 0

NNADVOKAT [17]

Answer:

x = -2 ± sqrt(5)

Step-by-step explanation:

x^2 + 4x – 1= 0

Add 1 to each side

x^2 + 4x – 1+1= 0+1

x^2 +4x = 1

Take the coefficient of x

Divide by 2

4/2 =2

Square it

2^2=4

Add it to each side

x^2 +4x+4=1+4

(x+2)^2 = 5

Take the square root of each side

sqrt((x+2)^2 )=± sqrt(5)

x+2 = ± sqrt(5)

Subtract 2 from each side

x+2-2 = -2 ± sqrt(5)

x = -2 ± sqrt(5)

8 0

2 years ago

Find the factors of 4x2-16x-9.

zzz [600]

Answer:

Step-by-step explanation:

$4x^2-16x-9.\\Writ -16x - as -a -difference\\ 4x^2 +2x-18x -9 \\Factor -out- common- terms\\2x(2x+1)-9(2x+1)\\ Factor -out (2x+1)\\(2x+1)(2x-9)$

I Hope It Helps :)

5 0

2 years ago

Read 2 more answers

The slope in the simplest form

masha68 [24]

Y=5/5x+ 5 or y=1 x + 5

8 0

1 year ago

A person breathes 2.5 x 10^-4 in about cubic meters of air per second. How long does it take to breathe in 2.5 cubic meters of a

Ipatiy [6.2K]

Answer:

10⁴ seconds

Step-by-step explanation:

Given that,

A person breathes $2.5\times 10^{-4}$ in about cubic meters of air per second.

We need to find time taken to breathe 2.5 cubic meters of air.

In 1 sec = $2.5\times 10^{-4}$ m³ of air breathe

Let in x seconds, 2.5 m³ of air taken by the person.

$x=\dfrac{2.5}{2.5\times 10^{-4}}\\\\x=10^4\ s$

Hence, in 10⁴ seconds 2.5 m³ of air is taken by the person.

5 0

2 years ago