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3 years ago

13

a ball bounces back .6 of its height on every bounce. if a ball dropped from 200 feet, how high does it bounce on the fifth boun

ce.

1 answer:

Ivanshal [37]3 years ago

3 0

15.552, 200 times .6 is 120, 120 times .6 is 72, 72 times .6 is 43.2, 43.2 times .6 is 25.92, 25.92 times .6 is 15.552

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Need help! ASAP! With algebra

dimaraw [331]

Answer:

2;4;3

Step-by-step explanation:

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2 years ago

Simplify the expression. Write the answer using scientific notation. (5x10^5)^-2 A. 0.04x10^-10 B. 4.0x10^-11 C. -10x10^-10 D. 4

Diano4ka-milaya [45]

Simplify the expression

$(5*10^5)^-2$

It can be simplified as below:

$(5*10^5)^{-2}=\frac{1}{(5*10^5)^2} \\\\(5*10^5)^{-2}=\frac{1}{25*10^{10}} \\\\(5*10^5)^{-2}=\frac{1}{25}*10^{-10}\\\\ (5*10^5)^{-2}=0.04*10^{-10}\\$

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3 years ago

Divide the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending power

aev [14]

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<span>3x - 7 </span>

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3 years ago

Point A (-7,-2) is rotated 270 counterclockwise and then shifted down 3 units. What are to coordinates of K’

AfilCa [17]

Answer:

K'= (-2, 4)

Step-by-step explanation:

First we are going to rotate our point 270° counterclockwise.

The rule for a 270° counterclockwise rotation is $(x,y)-->(y,-x)$ , which means that we just need to interchange the coordinates of the point and change the sign of the x-coordinate:

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$(-7,-2)-->(-2,-(-7))$

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Now, to shift the point 3 units down, we just need to subtract 3 units from the new y-coordinate of our resulting point form the previous procedure:

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3 years ago

What is the solution set of x 2 + 5x - 5 = 0?

mart [117]

X^2 + 5x - 5 = 0
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a = 1, b = 5, c = -5
x = (-5 +- sqrt(25+20))/2
x = (-5 +- sqrt(45))/2
x = (-5 + - 3 sqt 5))/2
x = (-5 + 3sqrt5)/2 and x = (-5 - 3sqrt5)/2

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3 years ago

Read 2 more answers