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2 years ago

Define equivalent expressions. Give an example of two equivalent expressions.

Mathematics

1 answer:

Tasya [4]2 years ago

3 0

Answer:

Hello There!

Step-by-step explanation:

Equivalent expressions are expressions that work the same even though they look different.

Examples of two equivalent expressions are:

-4(x + 2) and 4x + 8

-2y+5y−5+8 and 7y+3

These are equivalent expressions as they have the same value.

hope this helps,have a great day!!

~Pinky~

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Knut had picked strawberries during the summer holidays. First days he picked 9090 baskets of strawberries! The next day he was

jasenka [17]

Answer:

190 baskets of strawberries

Step-by-step explanation:

The question is incomplete as it didn't state what we are to determine from the information given.

Let's determine total amount picked in the three days.

1st day picked 90strawberries

Amount of strawberries on 2nd day = 2/3 of the amount picked 1st day

= (2/3)(90)

Amount of strawberries on 2nd day = 60 baskets of strawberries

Amount of strawberries picked on 3rd day = (2/3) of the amount picked 2nd day

= (2/3) (60)

Amount of strawberries picked on 3rd day = 40 basket of strawberries

Total amount picked for 3 days = 90+60+40

= 190 baskets of strawberries

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3 years ago

Find the interquartile range for the data {5, 7, 9, 5, 6, 6, 6, 11, 11, 3, 3}

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Answer:

Step-by-step explanation:

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2 years ago

Which net represents this triangular prism?

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Answer:

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2 years ago

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James spent no more than $20 at the mall. Write an inequality to represent how much James spent.

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Answer:

Step-by-step explanation:

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The time needed for all college students to complete a certain paper-and-pencil maze follows a normal distribution with a popula

oee [108]

Answer:

The correct option is a

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 30\ seconds$

The standard deviation is $\sigma = 3 \ seconds$

The sample size is n = 9

The null hypothesis is $H_o: \mu = 30$

The alternative hypothesis is $H_a : \mu \ne 30$

The level of significance is $\alpha = 0.01$

The sample mean is $\= x = 31.2$

Generally the test statistics is mathematically represented as

$z = \frac{ \= x - \mu }{ \frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{ 31.2 - 30}{ \frac{3}{\sqrt{9} } }$

=> $z = 1.2$

From the z table the area under the normal curve to the right corresponding to 1.2 is

$P(Z > 1.2) = 0.11507$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z > 1.2)$

=> $p-value = 2 *0.11507$

=> $p-value = 0.230$

From the value obtained w can see that

$p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is there is not enough evidence to support the claim

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2 years ago