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yaroslaw [1]
2 years ago
14

Can someone help me with this i am confused

Mathematics
1 answer:
Eva8 [605]2 years ago
6 0
Plot each point on a graph , then count how many you need to go up and then over in this case it is 8 over 1 then calculate the y int so y= 8x -25
You might be interested in
Seven less than three times a number is 5. Find the number
Anit [1.1K]

Step-by-step explanation:

it is 12 because 12 - 7 is 5 the number 4 is the number multiplied by 3

7 0
2 years ago
Read 2 more answers
Help me please Only no.2 no.3 no.8 no.6 no.9 and no.10
Reil [10]

Answer:

2) x³ (x² + 1) (x + 1)

3) (x - 6) (x + 6)

6)  (x + 3) (x - 4)

8) (5x + 3) (x - 2)

Step-by-step explanation:

I'm providing the solutions for numbers 2, 3, 6, and 8, in order to give you the opportunity to apply and practice the techniques demonstrated here for numbers 9 and 10.

<h3>2) x⁶ + x⁵ + x⁴ + x³ = 0 </h3>

Factor out the highest possible common term, applying the product rule of exponents, a^{m} a^{n} = a^{m+n}

x³ (x³ + x² + x¹ + 1) = 0

Next, apply the special factoring technique into the exponential expressions inside the parenthesis), the factor by grouping:

The factors for the given polynomial are: x³ (x² + 1) (x + 1)

<h3> 3) x² - 36 = 0 </h3>

Use the <u>difference of two squares factoring</u>, where it states: u² - v² = (u - v) (u + v)

Since 36 is a perfect square of 6², then we can establish the following factors using the difference of squares:

Factors:  (x - 6) (x + 6).

<h3>6) x² - x - 12 = 0 </h3>

For this quadratic trinomial, find factors that will produce a product of <em>a</em> × <em>c</em> (1 × -12) and sum of b (-1):

The possible factors of -12 that also results to a sum of -1 are:  

3 × -4 = -1

 Hence, the possible factors of x² - x - 12 = 0 could be (x + 3) (x - 4). Verify whether this is correct by performing the FOIL method:

(x + 3) (x - 4) = x² - 4x + 3x - 12 = x² - x - 12

Therefore, the factors of x² - x - 12 = 0 are: (x + 3) (x - 4).

<h3>8) 5x² - 7x - 6 = 0 </h3>

where a = 5, b = -7, and c = -6

Given this quadratic trinomial, we can use the factoring by grouping, where it states: find the values of u and v such that the product of uv is the same as the product of <em>ac</em>:  u × v = a × c, and that the sum of (<em>u</em> + <em>v </em>) is the same as <em>b</em>.  

In other words, we must find the factors of u × v that have a product of a × c and a sum of b:

<em>u × v </em>= <em>a × c</em> = 5 × (-6) = -30  

u + v = b = -7

The possible factors of -30 are:

-3 × 10 = -30

3 × -10 = -30

Out of these factors, the factors 3 × -10 = -30 will have the same sum as the value of b = -7:

3 + (-10) = -7

Hence, u = 3, v = -10.

Now, we can group the trinomial as follows:

(<em>ax</em>² + <em>ux </em>) + (<em>vx </em>+ <em>c </em>)

(5x² + 3x) + (-10x - 6)

For the last step, factor out the common terms from both groups:

(5x² + 3x) + (-10x - 6)  

x (5x + 3) - 2(5x + 3)

Combine common terms together: (5x + 3) and (x - 2)

Therefore, the factors of the given quadratic trinomial are: (5x + 3) (x - 2).

5 0
2 years ago
Two solutions to y'' – 2y' – 35y = 0 are yı = e, Y2 = e -5t a) Find the Wronskian. W = 0 Preview b) Find the solution satisfying
pashok25 [27]

Answer:

a.w(t)=-12e^{2t}

b.y(t)=-\frac{9}{2}e^{7t}-\frac{5}{2}e^{-5t}

Step-by-step explanation:

We have a differential equation

y''-2 y'-35 y=0

Auxillary equation

(D^2-2D-35)=0

By factorization method we are  finding the solution

D^2-7D+5D-35=0

(D-7)(D+5)=0

Substitute each factor equal to zero

D-7=0  and D+5=0

D=7  and D=-5

Therefore ,

General solution is

y(x)=C_1e^{7t}+C_2e^{-5t}

Let y_1=e^{7t} \;and \;y_2=e^{-5t}

We have to find Wronskian

w(t)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}

Substitute values then we get

w(t)=\begin{vmatrix}e^{7t}&e^{-5t}\\7e^{7t}&-5e^{-5t}\end{vmatrix}

w(t)=-5e^{7t}\cdot e^{-5t}-7e^{7t}\cdot e^{-5t}=-5e^{7t-5t}-7e^[7t-5t}

w(t)=-5e^{2t}-7e^{2t}=-12e^{2t}

a.w(t)=-12e^{2t}

We are given that y(0)=-7 and y'(0)=23

Substitute the value in general solution the we get

y(0)=C_1+C_2

C_1+C_2=-7....(equation I)

y'(t)=7C_1e^{7t}-5C_2e^{-5t}

y'(0)=7C_1-5C_2

7C_1-5C_2=23......(equation II)

Equation I is multiply by 5 then we subtract equation II from equation I

Using elimination method we eliminateC_1

Then we get C_2=-\frac{5}{2}

Substitute the value of C_2 in  I equation then we get

C_1-\frac{5}{2}=-7

C_1=-7+\frac{5}{2}=\frac{-14+5}{2}=-\frac{9}{2}

Hence, the general solution is

b.y(t)=-\frac{9}{2}e^{7t}-\frac{5}{2}e^{-5t}

7 0
2 years ago
A 15 | tall adult giraffe standing next to a ladder casts a 5 ft shadow. If the ladder is 12 ft tall, then how long is its shado
natima [27]

Answer:

Step-by-step explanation: bjffngjkldsldgns

3 0
2 years ago
Where the fine baddies at? hmu
Lady_Fox [76]

Answer:

not here-

Step-by-step explanation:

thanks for the points

6 0
3 years ago
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