Answer:
The area of the given figure is 
.
Step-by-step explanation:
To find out the area we should have to redraw the figure having nomenclature ABCDE and join BD. Thus we have a rectangle ABDE and a triangle BCD.
The new figure is in the attachment.
Given,
Length of AE = 7 cm
Length of DE = 8 cm
Length of CF = 11 cm
Solution,
Area of rectangle ABDE = 
Area of ABDE = 
Now for triangle BCD,
Length of BD = length of AE = 7 cm
Length of GF = Length of DE = 8 cm
∴ Length of CG = Length of CF-Length of GF = 
Area of triangle BCD = 
Area of BCD = 
Area of ABCDE = Area of ABDE + Area of BCD = 
Thus the area of the given figure is .
The answer would be 79 because the dog punched the alpaca
answer is 9
Change the sign of the exponent by rewriting the base as its reciprocal
3^2
raise 3 to the power of 2
you get 9
If the degree is even, then both ends of the graph go in the same direction, either both up or both down
if the degree is odd then both ends go in oposite directions
if the leading coefient (coefient of the highest powerd placeholder) is negative, then 2 possiblities could happen
1. if the degree of te function is even, then both ends point up
2. if the degree is odd, then the ends go from top left to bottom right
so we've got f(x)=-4x^6+6x^2-52
even degree and negative
so both ends point down
goes from bottom left to bottom right
B and D are the answers
