50% markup of $111.00 is the same as increasing 111 by half
50% of 111 = 55.5
Then add 55.5 on 111 = $166.50
Final value $166.50
We're looking for a solution of the form
with derivatives
Substituting these into the ODE gives
Shifting indices to get each term in the summand to start at the same power of 
and pulling the first few terms of the resulting shifted series as needed gives
Then the coefficients in the series solution are given according to the recurrence
Given the complexity of this recursive definition, it's unlikely that you'll be able to find an exact solution to this recurrence. (You're welcome to try. I've learned this the hard way on scratch paper.) So instead of trying to do that, you can compute the first few coefficients to find an approximate solution. I got, assuming initial values of 
, a degree-8 approximation of
Attached are plots of the exact (blue) and series (orange) solutions with increasing degree (3, 4, 5, and 65) and the aforementioned initial values to demonstrate that the series solution converges to the exact one (over whichever interval the series converges, that is).
Answer:
I believe the correct options are 1, 4, and 5.
Answer:
c = 0.75j
Step-by-step explanation:
divide $4.50 by 6 to find the price of one bottle of pineapple juice
4.50/6 = 0.75
each bottle of pineapple juice is 75 cents each
c = 0.75j
Answer: A=750 +75*t
B=900 +25*t
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Step-by-step explanation:
A = B
750 +75*t=900 + 25*t
Solving:
75*t -25*t= 900 - 750
50*t= 150
t=3
This indicates that in year 3 both High Schools are projected to have the same number of students. To get that amount, you simply replace this value in the expressions:
A=750 +75*t= 750 +75*3= 975
B=900 + 25*t=900 + 25*3= 975
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
