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____ [38]
3 years ago
10

Limit as x approaches 0 of (sin^2x)/x

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

<h3>0</h3>

Step-by-step explanation:

Given the expression

\lim_{x \to \ 0} \frac{sin^2x}{x}

Substitute the value of x in the function

= \frac{sin ^2(0)}{0}\\= 0/0 (indeterminate) \\

Apply l'hospital rule

\lim_{x \to \ 0} \frac{d/dx(sin^2x)}{d/dx(x)}  \\=  \lim_{x \to \ 0} \frac{(2sinxcosx)}{1}  \\

Substitute the value of x

= 2 sin(0)cos(0)

= 2 * 0 * 1

= 0

Hence the limit of the function is 0

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