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Mrac [35]
3 years ago
12

-8 + 2/3x + 4 = 2x -5-x

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
8 0

Answer:

3

Step-by-step explanation:

Let's isolate x on one side.

2x - x - 2/3x = -8+5+4

1/3x=1

x=3

atroni [7]3 years ago
7 0

Answer:

X = 3

Step-by-step explanation:

-8 + 2/3x + 4 = 2x - 5 - x

2/3x - 2x - x = -5 + 8 - 4

-1/3x = -1

x = -1 * -3

x = 3

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Number 6 and 7 what is the answer please!
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2 years ago
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Solve and check:8a-4=25+6(a-8)
OlgaM077 [116]
8a - 4 = 25 + 6 (a - 8)

(distribute the 6)

8a - 4 = 25 + 6a - 48

(combine like terms 25 - 48)

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( subtract 6a from both sides)

2a - 4 = -23

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(divide both sides by 2)

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////CHECK/////

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(plug each side into a calculator)

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5 0
3 years ago
A cylindrical tank with radius 3 m is being filled with water at a rate of 4 m3/min. How fast is the height of the water increas
Fittoniya [83]

Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>How to solve?</h3>

With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

#V=pi r^2 h#

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

#V=pi (5m)^2 h#

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

#(dV)/(dt)=(25 m^2) pi (dh)/(dt)#

In the problem, we are given #3(m^3)/min# which is #(dV)/(dt)#.

So we need to substitute this in:

#(dh)/(dt)=(3m^3)/(min (25m^2) pi)=3/(25 pi)m/(min)#

Hence,  Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>Formula used: </h3>

#V=pi r^2 h#

To Learn more visit:

brainly.com/question/4313883

#SPJ4

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2 years ago
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Simplify 400:240 fully
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40:24
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5:3
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