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3 years ago

The point (-3/5,y) in the third quadrant corresponds to angle θ on the unit circle.

1 answer:

7 0

Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate

hypotenuse = 1 (because it is the radius of the unit circle)

sec (theta) = 1 / (-3/5) = - 5/3

cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate

cot (theta) = -3/5 / y

y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5

Third quadrant => y = -4/5

=> cot (theta) = (-3/5) / (-4/5) = 3/4

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Four times the sum of 4 and some number is 40

pochemuha

4 + 6 = 10

10 * 4 = 40.

The full equation looks like this....

4(4+6)

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3 years ago

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A movie theater earned $3,600 in sold-out ticket sales for the premiere of a new movie. VIP tickets cost $20 per person and regu

julia-pushkina [17]

There are 300 seats in the theater.

Step-by-step explanation:

Given,

Cost of one VIP ticket = $20

Cost of one regular ticket = $8

Worth of sold out tickets = $3600

Let,

x represent the number of VIP tickets sold

y represent the number of regular tickets sold

20x+8y=3600 Eqn 1

y = 2x Eqn 2

Putting value of y from Eqn 2 in Eqn 1

$20x+8(2x)=3600\\20x+16x=3600\\36x=3600$

Dividing both sides by 36

$\frac{36x}{36}=\frac{3600}{36}\\x=100$

Putting x=100 in Eqn 2

$y=2(100)\\y=200$

Total = x+y = 100+200 = 300

There are 300 seats in the theater.

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

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3 years ago

What is 1037 /61 in standard form

JulijaS [17]

Y=17 If it's just 1037/61

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3 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

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3 years ago

What are the solutions for the given equation?

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Answer:

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Step-by-step explanation:

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2 years ago