The transformation is ISOMETRY.
In mathematics, an isometry<span> (or congruence, or congruent transformation) is a distance-preserving transformation between metric spaces, usually assumed to be bijective. A composition of two opposite </span>isometries<span> is a direct </span>isometry<span>. A reflection in a line is an opposite </span>isometry<span>, like R </span>1<span> or R </span>2<span> on the image.</span>
The answer would be 0.15 because in a deck there are only 4 cards of 8 (diamonds, hearts, clovers, and spades). Since there are 52 cards, you would divide 8 by 52 to get 0.153846, but since it says to round to the nearest hundredths, the answer would be 0.15.
1) 4 2/5 +1/5 = D)4 3/5
2)5 6/9- 1/3 = 5 1/3 or 16/3
Answer:
The function represents a direct variation
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form 
or 
In a linear direct variation the line passes through the origin and the constant of proportionality k is equal to the slope m
Let
------> the line passes through the origin
Find the value of k------> substitute the value of x and y
-----> 
Find the value of k------> substitute the value of x and y
-----> 
Find the value of k------> substitute the value of x and y
-----> 
Find the value of k------> substitute the value of x and y
-----> 
The value of k is equal in all the points of the table and the line passes through the origin
therefore
The function represents a direct variation
the equation of the direct variation is equal to
5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
