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3 years ago

14

Who wants to play truth or dare use the comments and stay on till the game is over and comment down below if you have to leave s

o we know.

1 answer:

solmaris [256]3 years ago

5 0

I mean I will play I guess but how do you do dare

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Correctly identify the property shown.

sleet_krkn [62]

It is Associative Property

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3 years ago

The average radius of Jupiter is 4.34 x 10^4 miles. The average sun radius of the sun is 4.32 x 10^5. How many times greater is

Oksanka [162]

Answer:

The average radius of sun is approximately 9.95 times the average radius of Jupiter.

Step-by-step explanation:

We are given the following in the question:

Average radius of Jupiter =

$4.34\times 10^{4}\text{ miles}$

Average radius of the sun =

$4.32\times 10^{5}$

Relation between average radius of sun and average radius of Jupiter =

$\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}}\\\\= \frac{4.32\times 10^{5}}{4.34\times 10^{4}}\\\\\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}} = 9.953917\\\\\text{Average radius of Sun} \approx 9.95\times \text{(Average radius of Jupiter)}$

Thus, the average radius of sun is approximately 9.95 times the average radius of Jupiter.

7 0

3 years ago

Find the vertex for the equation: y=-2x^2+16x-31

Nutka1998 [239]

Answer:

Vertex is (4,1)

Step-by-step explanation:

x=-b/2a so you need to first divide the b (second term) by the a (first term) so you should get 1 as your new a and -8 as your new b. Negative (-8) is just 8 then divide that by 2(1) which is just 2 which equals 4. That is your x. To find your y, you plug your x back into the original equation and then solve it. Hope this helps!

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3 years ago

Line segment C X is an altitude in triangle ABC. Triangle A B C is shown. Angle A C B is a right angle. An altitude is drawn fro

Alenkinab [10]

Answer:

i. ΔAXC ~ ΔCXB

ii. ΔBCX Is-congruent-to ΔACX

Step-by-step explanation:

From the given ΔABC, CX is the altitude of ΔABC; and also an angle bisector of <ACB.

So that:

m<AXC = m<BXC (right angle property)

m<ACX = m<BCX (congruent property)

m<ACX + m<AXC + m<CAX = $180^{o}$ (sum of angles in a triangle)

m<BCX + m<BXC + m<CBX = $180^{o}$ (sum of angles in a triangle)

Therefore, from the figure it can be deduced that;

i. ΔAXC ~ ΔCXB (Angle-Angle-Side, AAS, property)

ii. ΔBCX Is-congruent-to ΔACX (Angle-Angle-Side, AAS, property)

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3 years ago

Read 2 more answers

Find the value of each trigonometric ratio. Simplify

AysviL [449]

Tan = opp/adj

Tan A = 16/12

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2 years ago