So Jada for 1 day, gets charged $30 flat
now, she drove 2 days, so...she's charged 2 * 30 or 60 bucks
plus the mileage
is 0.5 per mile.... so... 1 mile is 0.5
2 miles 2 * 0.5
3 miles 3 * 0.5
4 miles 4 * 0.5
5 miles 5 * 0.5
x miles x * 0.5
she drove "x" miles, whatever that is
we also know, her total cost in the end, was 360
so... those 360 include the 2 days charge, 30 * 2
plus the mileage, x * 0.5 or 0.5x
so... one can say that
360 = (30 * 2) + 0.5x <---- solve for "x"
Answer:
y = 2x or x = 1/2y or if you would like numerical values then x = 3, y = 6 and z=4
Step-by-step explanation:
x : y = 1 : 2
y : z = 3 : 2
If x : y = 1 : 2 then we know that 1y = 2x ∴ y = 2x or x = 1/2y
If y : z = 3 : 2 then we know that 3z = 2y ∴ z = 2/3y
Answer:
1 : 2 : 1
Step-by-step explanation:
2:4:2
Divide each term by 2
2/2:4/2:2/2
1 : 2 : 1
D. Because Ram only did 2 hours so then that makes 2 hours of work done but then left for whatever reason. Ajit left 3 hours BEFORE the completion of the work and that gives us info that there were hours put in between both Rams and Ajits work. They all started at the same time so it doesn't mean that Ajit didn't do any of the work. Ajit can work for 12 hours POSSIBLY. It did not say he can exact. So it leaves to Suresh that can work up to 15 hours of the work but we dont know how long he did it. Suresh either could just gone over or less than 15 hours.
Is there an image? Or a multiple choice?