The value of the coefficient B is 9.
2(x+By)(x-2y)
=2(x^2 -2xy +Bxy -2By^2)
=2x^2 -4xy + 2Bxy - 4By^2
The original form is 2x^2 + 14xy - 36y^2
-36y^2 = -4By^2
B= 9
-4xy +2Bxy= 14xy
xy(-4 +2B)= 14xy
-4 + 2B = 14
2B = 18
B=9
Given that the associative property of multiplication says that you can group the numbers in any combination, we can reorganize the expression as: 7·(10·3)=210. So the answer would be the first option.
Given:
The equations of parabolas in the options.
To find:
The steepest parabola.
Solution:
We know that, if a parabola is defined as

Then, the greater absolute value of n, the steeper the parabola.
It can be written as


where
, the smaller absolute value of p, the steeper the parabola.
Now, find the value of |p| for eac equation
For option A, 
For option B, 
For option C, 
For option D, 
Since, the equation is option A has smallest value of |p|, therefore, the equation
represents the steepest parabola.
Hence, the correct option is A.
Answer:
0≥x<4
Step-by-step explanation:
first, let's look at this number line.
there is a closed circle at 0 and an open circle at 4. this means that 0 is included (≤ or ≥) and that 4 is not included (< or >).
these are the endpoints, meaning that in this compound inequality, the numbers next to the symbols are 0 and 4.
x is in the middle of this compound inequality.
0 x 4
now, we have to figure out the symbols in between. i wrote out our choices above for each number. the highlighted portion is greater than or equal to 0 and less than 4, so we can write this compound inequality as the following:
0≥x<4
x is greater than or equal to 0, but less than 4