Two sides of a right triangle measure 2 units and 4

Mathematics

1 answer:

fredd [130]3 years ago

8 0

Hey there!

The answer is √20 or approximately 4.47

We can use the Pythagoreon Theorem, which is $a^2 +b^2=c^2$ . $a$ and $b$ are the names of the two sides, and $c$ is the name of the hypotenuse leg, or the longest side. We will plug the numbers into the formula, and solve:

$2^2+4^2=c^2\\4+16=c^2\\20=c^2\\4.47...=c$

Have a terrifcly amazing day!

You might be interested in

Simplify : 7x^2 + 6x + 9x^2 - 5x

anastassius [24]

Answer:

131x

Step-by-step explanation:

7x² + 6x + 9x² - 5x

49x + 6x + 81x - 5x

136x - 5x

131x

7 0

3 years ago

Help plz 20 pts TOTAL 10 pts each

motikmotik

Answer:

This question needs a step to step long explanation.

5 0

3 years ago

In f(x) = 2x2 − 8x − 10, the y-intercept is ? at ? and the x-intercepts are (-1, 0) and ? .

IgorLugansk [536]

<h2>1. y-intercept</h2>

$\boxed{(0,-10)}$

The quadratic function $f(x)=2x^22-8x-10$ represents a parabola. In fact, the graph of a quadratic function is a special type of U-shaped curve called a parabola. To find the y intercept, we set $x=0$ as follows:

$f(x)=2x^2-8x-10 \\ \\ If \ x=0 \rightarrow f(0)=-10 \\ \\ Then \ y-intercept: \\ \\ (0,-10)$

<h2>2. x-intercepts</h2>

$\boxed{(-1,0) \ and \ (5,0)}$

To find the other x-intercept, we must set $y=0$ as follows:

$f(x)=2x^2-8x-10 \\ \\ If \ y=0 \rightarrow 2x^2-8x-10=0 \\ \\ Using \ the \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \therefore x=\frac{-(-8) \pm \sqrt{(-b)^2-4(2)(-10)}}{2(2)} \\ \\ \therefore x_{1}=-1 \ and \ x_{2}=5$