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Nadusha1986 [10]
3 years ago
11

In f(x) = 2x2 − 8x − 10, the y-intercept is ? at ? and the x-intercepts are (-1, 0) and ? .

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0
<h2>1.  y-intercept</h2>

\boxed{(0,-10)}

The quadratic function f(x)=2x^22-8x-10 represents a parabola. In fact, the graph of a quadratic function is a special type of U-shaped curve called a parabola. To find the y intercept, we set x=0 as follows:

f(x)=2x^2-8x-10 \\ \\ If \ x=0 \rightarrow f(0)=-10 \\ \\ Then \ y-intercept: \\ \\ (0,-10)

<h2>2.  x-intercepts</h2>

\boxed{(-1,0) \ and \ (5,0)}

To find the other x-intercept, we must set y=0 as follows:

f(x)=2x^2-8x-10 \\ \\ If \ y=0 \rightarrow 2x^2-8x-10=0 \\ \\ Using \ the \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \therefore x=\frac{-(-8) \pm \sqrt{(-b)^2-4(2)(-10)}}{2(2)} \\ \\ \therefore x_{1}=-1 \ and \ x_{2}=5

Therefore, the other x-intercept is (5,0). You can see both the y-intercept and the x-intercepts in the figure below.

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