Answer:
yes ofc boiiiiii 3 tens=30 ones boiiii and 25 ones=2 tens and 5 ones boiiiii
Step-by-step explanation:
Answer:
I think it may be six , but I may be wrong
Step-by-step explanation:
Answer:
y=8x or y=8x + 0
Step-by-step explanation:
you need to take 2 points on the lina and make a triangle i used (-2,16) and (0,0).
The equation for gradient is
![\frac{rise}{run} = \frac{16}{2} = 8](https://tex.z-dn.net/?f=%20%5Cfrac%7Brise%7D%7Brun%7D%20%20%20%3D%20%20%5Cfrac%7B16%7D%7B2%7D%20%20%3D%208)
and the line touches the Y-axis at 0(that is your y-intercept)
Answer:
243
Step-by-step explanation:
make 90% into a decimal
0.9
multiply 270 by 0.9 to get the answer of 243
Given:
The surface area of a right circular cone is 32 sq. cm.
Scale factor for enlargement = 3
To find:
The surface area of the new cone.
Solution:
We know that enlargement of a shape forms a similar shape and area of the similar shapes is proportional to the square of their corresponding sides.
![\dfrac{\text{Area of cone}}{\text{Area of new cone}}=\dfrac{\text{Radius of cone}^2}{\text{Radius of new cone}^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BArea%20of%20cone%7D%7D%7B%5Ctext%7BArea%20of%20new%20cone%7D%7D%3D%5Cdfrac%7B%5Ctext%7BRadius%20of%20cone%7D%5E2%7D%7B%5Ctext%7BRadius%20of%20new%20cone%7D%5E2%7D)
Let the surface area of new cone be A and r be the radius of original cone
![\dfrac{32}{A}=\dfrac{(r)^2}{(3r)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B32%7D%7BA%7D%3D%5Cdfrac%7B%28r%29%5E2%7D%7B%283r%29%5E2%7D)
![\dfrac{32}{A}=\dfrac{r^2}{9r^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B32%7D%7BA%7D%3D%5Cdfrac%7Br%5E2%7D%7B9r%5E2%7D)
![\dfrac{32}{A}=\dfrac{1}{9}](https://tex.z-dn.net/?f=%5Cdfrac%7B32%7D%7BA%7D%3D%5Cdfrac%7B1%7D%7B9%7D)
By cross multiplication, we get
![32\times 9=1\times A](https://tex.z-dn.net/?f=32%5Ctimes%209%3D1%5Ctimes%20A)
![288=A](https://tex.z-dn.net/?f=288%3DA)
The surface area of the new cone is 288 sq. cm.
Therefore, the correct option is C.