Question

Three consecutive multiples of 2 is 36 then the multiples are​

Answer 1

Answer:

9, 12, 15

A multiple of 3 can be written 3n where n is a positive integer.

So 3 consecutive multiples of 3 can be written

3n,3n+3,3n+6

The sum of these is 36

3n+3n+3+3n+6=36

9n+9=36

Divide through by 9

n+1=4

n=3

If n=3 then 3n=9 and the three consecutive multiples of three are 9, 12 and 15 which do indeed total 36

Step-by-step explanation:

Hope it is helpful....