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AnnZ [28]
4 years ago
11

(03.06 MC)Solve the equation for the letter r: d = rt

Mathematics
2 answers:
kiruha [24]4 years ago
5 0

Answer:

r = \frac{d}{t}

Step-by-step explanation:

Given: d = rt

Here we have to solve for letter "r".

To solve for letter "r" we have to use inverse operation and solve.

d = rt

We have to get rid of "t" on the right hand side.

"t" is in the multiplication, the inverse operation of multiplication is division.

So divide both sides by t, we get

d/t = rt/t

Simplifying the above equation, we get

d/t = r

Therefore, r = \frac{d}{t}

Neporo4naja [7]4 years ago
4 0
The equation for r: d = rt would be 'r equals d over t.'

How, you might ask? Well, let's consider this example:

You might already know what d = rt stands for... "Distance equals rate times time", so if you divide the two sides by 't', you would come up with r = d/t. So that would finalize as your answer for this question.
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4 years ago
A study of pollutants showed that certain industrial emissions should not exceed 2.3 parts per million. You believe a particular
Musya8 [376]

Answer:

t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5    

The degrees of freedom are given by:

df=n-1=9-1=8  

And the p value would be:

p_v =P(t_{(8)}>7.5)=0.0000346  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

Step-by-step explanation:

Information provided

\bar X=3.3 represent the sample mean in ppm

s=0.4 represent the sample standard deviation

n=9 sample size  

\mu_o =2.3 represent the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value

System of hypothesis

We want to verify if the true mean is higher than 2,3 ppm, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.3  

Alternative hypothesis:\mu > 2.3  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5    

The degrees of freedom are given by:

df=n-1=9-1=8  

And the p value would be:

p_v =P(t_{(8)}>7.5)=0.0000346  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

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-Dominant- [34]
It is already given in the problem that the area of the triangle logo is 36 square units and the area of the rectangle is 54 square units. Considering that there are no additional places in the logo except the triangle and the rectangle, we have to determine the percentage of the total area of the logo covered by the triangle.
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Total area covered by the triangle and the rectangle logo = (36 + 54) square units
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Then
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